The order of the energy of the photons of given wave will be
= Ultraviolet waves > infrared waves > microwaves
where,
E = energy of photon
= frequency of the radiation
h = Planck's constant = ×
⁻³⁴
We have :
(a) Frequency of infrared waves = ₁ =
×
¹³
(b) Frequency of microwaves= ₂ =
×
¹¹
(c) Frequency of ultraviolet waves = ₃ =
×
¹⁵
So, the decreasing order of the frequencies of the waves will be :
₃
₁
₂
As we can see from the formula that energy is directly proportional to the frequency of the wave.
∝
So, the order of the energy of the photons of given wave will be same as their order of frequencies:
₃>
₁ >
₂
= Ultraviolet waves > infrared waves > microwaves
Also the complete question is :
Rank the following photons in terms of decreasing energy:
(a) IR (v = 6.5 x 10¹³ s⁻¹)
(b) microwave (v = 9.8 x 10¹¹ s⁻¹)
(c) UV (v = 8.0 x 10¹⁵ s⁻¹)
To learn more about microwaves visit the link:
#SPJ4