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Sever21 [200]
4 years ago
6

A total of 20.0 mL of sodium hydroxide (NaOH) was neutralized by 30.0 mL of 0.250 M hydrogen bromide (HBr). What was the concent

ration of the sodium hydroxide? I also need to know the Solution, Molar Ratio, Volume, and Concentration
Chemistry
1 answer:
Karolina [17]4 years ago
8 0

Answer:

0.375 M

Explanation:

NaOH(aq) + HBr(aq) ------------> NaBr(aq) + H2O(l)

Concetration of acid CA= 0.250M

Concentration of base CB= ????

Volume of acid VA= 30.0mL

Volume of base VB= 20.0mL

Number of moles of acid nA= 1

Number of moles of base nB= 1

CA VA/CB VB= nA/nB

CB= CAVAnB/VB nA

= 0.25× 30×1/20×1= 0.375 M

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3 years ago
Question 5 (1 point)
ollegr [7]

Answer:

0.00125 moles H₃X

Solution and Explanation:

In this question we are required to calculate the number of moles of triprotic acid neutralized in the titration.

Volume of NaOH used = final burette reading - initial burette reading

                                      = 39.18 ml - 3.19 ml

                                      = 35.99 ml or 0.03599 L

Step 1: Moles of NaOH used

Number of moles = Molarity × Volume

Molarity of NaOH = 0.1041 M

Moles of NaOH = 0.1041 M × 0.03599 L

                          = 0.00375 mole

Step 2: Balanced equation for the reaction between triprotic acid and NaOH

The balanced equation is;

H₃X(aq) + 3NaOH(aq) → Na₃X(aq) + 3H₂O(l)

Step 3: Moles of the triprotic acid (H₃X used

From the balanced equation;

1 mole of the triprotic acid reacts with 3 moles of NaOH

Therefore; the mole ratio of H₃X to NaOH is 1 : 3.

Therefore;

Moles of Triprotic acid = 0.00375 mole ÷ 3

                                     = 0.00125 moles

Hence, moles of triprotic acid neutralized during the titration is 0.00125 moles.

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4 years ago
What caused wind to blow
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Hope this helped and if it did, please give my answer a brainliest.

7 0
4 years ago
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Explanation:

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4 years ago
What is the concentration of nitrate ions in a 0.225 msr(no3)2 solution?
12345 [234]

Answer : The concentration of nitrate ions is 0.450 m.

Solution : Given,

Molarity of Sr(NO_3)_2 = 0.225 m

The balanced ionic equation is,

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From the reaction, we conclude that the 1 mole of Sr(NO_3)_2 produces 2 moles of NO^-_3 ions. That means the concentration of nitrate ions is twice the value of Sr(NO_3)_2.

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7 0
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