Answer:
They both include a question,procedure and conclusion.
Answer:
Solution's mass = 200.055 g
[PbSO₄] = 275 ppm
Explanation:
Solute mass = 0.055 g of lead(II) sulfate
Solvent mass = 200 g of water
Solution mass = Solvent mass + Solution mass
0.055 g + 200 g = 200.055 g
ppm = μg of solute / g of solution
We convert the mass of solute from g to μg
0.055 g . 1×10⁶ μg/ 1g = 5.5×10⁴μg
5.5×10⁴μg / 200.055 g = 275 ppm
ppm can also be determined as mg of solute / kg of solution
It is important that the relation is 1×10⁻⁶
Let's verify: 0.055 g = 55 mg
200.055 g = 0.200055 kg
55 mg / 0.200055 kg = 275 ppm
Answer:
B
Explanation:
Since ice is less dense than water, it floats. This forms an ice cover sheet in cold regions such as in the poles. This insulates the water beneath from excessive heat loss hence preventing it from turning into ice too, This protects the marine life beneath. Also, water does not gain heat or loss it rapidly (due to its high heat capacity) hence offering a more or stable temperature range for marine life.
Answer: 5.72 g mass of carbon dioxide was produced
Explanation:
Moles of C =
Mass of 
reacted = 59.1 g - 17.5 g = 41.6 g
Moles of 
According to reaction 1 mole produces 1 mole of 
then 1.3 mole of will produce 
moles of
Mass of :
=Moles of × molar mass of = 1.3 ×44 g/mol =
=57.2 grams
5.72 g mass of carbon dioxide was produced
