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2 years ago

What can crystalize size tell us about where an igneous rock formed?

Chemistry

1 answer:

Mila [183]2 years ago

4 0

Answer:

Crystalization is solidfying of atoms or molecules or things,,it can be speeded up depends on nature of something in terms of it's molecular force of attraction eg sand and loam soil also temperature and pressure above the sure to be crystalized

An igneus rock is formed where magma(molten rock) cool and solify(crystalized especially in volcanoes areas

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Which kind of energy does matter have when it is in motion?

Rzqust [24]

Answer:

Kinetic Energy

Explanation:

Kinetic energy is the energy inside moving objects of things.

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3 years ago

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Explain how fluorine and aluminum would exchange valence electrons to form an ionic compound.

o-na [289]

Answer :

Explanation :

The aluminium and fluorine react to give ionic compound aluminium fluoride.

Aluminium has 1 valence electrons in their shell and fluorine has 7 valence electrons in their shell.

For the complete octet, both aluminium and fluorine exchange valence electrons to form an ionic compound.

The aluminium donates its three valence electrons to three fluorine atoms and they form one $Al^{3+}$ and three $F^-$ ions.

Electron transfer image is shown below.

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3 years ago

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How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?

Kipish [7]

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

( V×C )acid = ( V×C )base

∴ C H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ C KOH = 0.0050 N = 0.0050 eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ C KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×C ) acid / C KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

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3 years ago

Which of the following procedures is used when refining petroleum? Increase the temperature of the oil. Decrease the temperature

Novosadov [1.4K]

Increase the tempature

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2 years ago

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Which is the limiting reactant if we start with 30.0 g Al and 30.0 h O2

lorasvet [3.4K]

Explanation:

The limiting reactant will be Al:

4Al + 3O₂ → 2Al₂O₃

The limiting reactant is the reactant in short supply in a chemical reaction.

Given parameters:

Mass of Al = 30g Molar mass = 27g/mol

Number of moles = $\frac{mass}{molar mass}$ = $\frac{30}{27}$

Number of moles of Al = 1.111 mole

Mass of O₂ = 30g, molar mass = 32g/mol

Number of moles = $\frac{30}{32}$ = 0.94mol

In the reaction:

4 moles of Al reacted with 3 moles of O₂

1.11moles of Al will require $\frac{1.11 x3}{4}$ = 0.83mole to react

But we have been given 0.94mole of O₂. This is more than required.

Therefore O₂ is in excess and Al is the limiting reactant.

Learn more:

Limiting reagents brainly.com/question/6078553

#learnwithBrainly

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2 years ago