Aren't you just multiplying both numerator and denominator by 10?
Answer: 50
(10)x= -7_______(i)
3x-5y= -16____(ii)
put value of x in (ii) then we have:-
3x-5y= -16
3(-7)-5y= -16
-21-5y= -16
-5y = -16+21
-5y = 5
y = 5/-5= -1
y= -1
(11)
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Hi, your question was incomplete hence I have attached the complete version of the question below.
Answer:
<u>5x^3 y^2</u>
Step-by-step explanation:
Using the property of the product of the exponents on the base and removing the parentheses,
(125x^9y^6)^(1/3) = (125)^(1/3) * (x^9)^(1/3) * (y^6)^(1/3)
= (125)^(1/3) * (x)^9*(1/3) * (y)^6*(1/3)
= 5 * (x)^3 * (y)^2
= 5 x^3 y^2
hence the required result is 5 x^3 y^2
<span>(4ab^3)(-5b^6)(2a^2)
= (5 * -4 * 2)(a * a^2)(b^3 * b^6)
= -40a^3b^9
hope it helps</span>