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storchak [24]
3 years ago
9

Two lab carts are pushed together with a spring mechanism compressed between them. Upon release, the 5.0 kg cart repels one way

with a velocity of 0.12 m/s. The 2.0 kg cart goes the other way. At what velocity does it travel?
Physics
1 answer:
JulijaS [17]3 years ago
8 0

Answer:

V = -0.3 m/sec.

Explanation:

5.0 x 0.12 + 2.0 x v = 0. Which means that V = -0.3 m/sec.

The -ve sign shows it moves in the opposite direction.

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A sound wave has a frequency of 300 Hz. If the wavelength is .50 m, then what is the speed of
kherson [118]

Answer:

15000 m/s

Explanation:

You just need to multiply the wavelength with the frequency.

7 0
2 years ago
) The radius of sphere measured repeated values 5.63 m, 5.54 m and 5.53 m. Determine the most
Nadusha1986 [10]

Answer:

v_{ average} = 5.57

Explanation:

The most probable value of a measure is

       v_average = \frac{1}{N} ∑ x_i

where N is the number of measurements

in tes case N = 3

         v_{average} = ⅓ (5.63 +5.54 + 5.53)

         V_{average} = 5,567

The number of significant figures must be equal to the number of figures that have the least in the readings.

          v_{ average} = 5.57

3 0
2 years ago
Two waves are superposed. one wave has an amplitude of 5 cm, and other has an amplitude of 4 cm. What is the resultant amplitude
Vsevolod [243]
If both waves have the same wavelength, then the amplitude of
their sum could be anything between 1 cm and 9 cm, depending
on the phase angle between them.

If the waves have different wavelengths, then the resultant is a beat
with an amplitude of 9 cm.
4 0
3 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 10 rev/s. If such a star has a radius of 18 k
Aleks [24]

Answer:

mass of the neutron star =3.45185×10^26 Kg

Explanation:

When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.

That is

\frac{GM_{ns}}{R^2}= \omega^2 R

M_ns = mass odf the netron star.

G= gravitational constant = 6.67×10^{-11}

R= radius of the star = 18×10^3 m

ω = 10 rev/sec = 20π rads/sec

therefore,

M_{ns}= \frac{\omega^2R^3}{G} = \frac{4\pi^2\times(18\times10^3)^3}{6.67\times10^{-11}}

= 3.45185... E26 Kg

= 3.45185×10^26 Kg

4 0
3 years ago
A cartoon shows two friends watching an unoccupied car in free fall after it has rolled off a diff. One friend says to the other
olga55 [171]

Answer:

The statement is not correct.

Explanation:

To know if the statement is correct, we shall determine the velocity of the car after 3 s. This is illustrated below.

Data obtained from the question include:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 3 s

Final velocity (v) =?

v = u + gt

v = 0 + (9.8 × 3)

v = 0 + 29.4

v = 29.4 m/s

Thus, the velocity of the car after 3 s is 29.4 m/s.

Hence, the statement made by the friend is not correct as the car has a falling velocity of 29.4 m/s after 3 s.

8 0
3 years ago
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