Answer is: there is 1,77·10²³ molecules of CH₂Cl₂.
m(CH₂Cl₂) = 25 g.
n(CH₂Cl₂) = m(CH₂Cl₂) ÷ M(CH₂Cl₂).
n(CH₂Cl₂) = 25 g ÷ 85 g/mol.
n(CH₂Cl₂) = 0,294 mol.
N(CH₂Cl₂) = n(CH₂Cl₂) · Na.
N(CH₂Cl₂) = 0,294 mol · 6,023 1/mol.
N(CH₂Cl₂) = 1,77·10²³.
n - amount of substance.
Na - Avogadro number.
Answer:
(a) 
(b) 
Explanation:
Hello,
(a) Based on the inlet conditions, we see that such carbon dioxide has an ideal behavior, so the inlet specific volume is:

Thus, the volumetric flow rate turns out:

(b) Now, by writing and energy balance we have:

Thus, since the ideal gas enthalpy does not depend on the pressure, in Cengel's A-20 table, the corresponding enthalpies at 300K and 450 K are 9431kJ/kmol and 15483kJ/kmol whose values in kJ/kg are 214.34 kJ/kg and 351.89 kJ/kg respectively, thus:

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Answer:
0.47m²
Explanation:
Given parameters:
Length = 9.025 x 10⁶m
Width = 5.215 x 10⁻⁸m
Unknown:
Area of the rectangle = ?
Solution:
Area is the derived from the product of the length and width of a body.
Area = length x width = 9.025 x 10⁶m x 5.215 x 10⁻⁸m
Area = 0.47m²
Answer:
The histosols of peat pogs are soils rich in organic material but poor in mineral nutrients, and are not fertile. Conversely, aridosols (desert soils) have an abundance of mineral nutrients but a dearth of organic matter and are also not fertile.
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