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RUDIKE [14]
3 years ago
10

What are the levels of orgamnization in a biome?

Chemistry
1 answer:
olga2289 [7]3 years ago
7 0
Here's a chart to help you! Start from the top to the bottom.

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A volume of 25cm3 of a carbonate solution of concentration 0.2mol dm-3 was neutralized by 20 cm3 of acid of concentration 0.5 mo
Galina-37 [17]

Answer: 1 mol of carbonate to 2 mol of acid

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}  

a) \text{Moles of carbonate}=\frac{0.2moldm^{-3}\times 25cm^3}{1000}=0.005mol

b) \text{Moles of acid}=\frac{0.5moldm^{-3}\times 20cm^3}{1000}=0.01mol

Thus the mole ratio of carbonate to acid is = \frac{0.005}{0.01}=\frac{1}{2}

7 0
3 years ago
The molar volume of gas at STP, in liters, is?
defon
<span>The molar volume of a gas at STP, in liters, is 22.4

you then multiply 22.4 by 2 to get the answer to the next question:
</span><span>
You can use the molar volume to convert 2 mol of any gas to 44.8 L
</span>
<span>You can also use the molar volume to convert 11.2 L of any gas to 0.500 mol.
</span>
Avogadro’s law tells you that 1.2 L of O2(g) and 1.2 L of NO2(g<span>) are the same </span><span>numbers of moles of gas.</span>

7 0
3 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
3 years ago
How many molecules are in 3.8 mols of copper?
ioda

Answer:

Hi there!

The correct answer is 2.29 x 10^{24} molecules

Explanation:

To convert from the moles to molecules:

1 mole = 6.022 x 10²³ molecules

so basically you multiply 3.8 by 6.022 x 10²³

and you get: 2.29 x 10^{24}

5 0
4 years ago
Definition of metallurgy
iragen [17]
<span>Definition of Metallurgy-The branch of science and technology concerned with the properties of metals and their production and purification.</span>
8 0
4 years ago
Read 2 more answers
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