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Luda [366]
3 years ago
13

Grams of CuCI please help 10 point

Chemistry
1 answer:
rosijanka [135]3 years ago
5 0
I DONOU I JEED HELP 629
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During science lab, some students added small pieces of magnesium ribbon to 10 mL of hydrochloric acid. They noticed that bubble
stiv31 [10]
Your answer would be a change in odor! Hope this helps! ;D
4 0
4 years ago
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In general, metalloids are slightly reactive.<br> true or false ?
Katarina [22]
TRUE

Compared with other metals, eg. groups 1 and 2, which are very reactive, and with some non metals, e.g. group 7, metalloids are less reactive.
7 0
4 years ago
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How many moles of water are in 1.23 times 10^18 water molecules
Radda [10]

Answer:

<h3>The answer is 0.000002 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.23\times  {10}^{18} }{6.02 \times  {10}^{23} }  \\  = 0.00002043...

We have the final answer as

<h3>0.000002 moles</h3>

Hope this helps you

7 0
3 years ago
The primary component of the soda lime used in the experimental chamber (calcium hydroxide) reacts to produce a white precipitat
solmaris [256]

Soda lime is a mixture primarily consisting of calcium hydroxide which is used to remove carbon dioxide gas ( CO2) from the surrounding medium.

The reaction of calcium hydroxide with carbon dioxide produces a white insoluble precipitate of calcium carbonate.

The chemical equation for the reaction is given below.

Ca(OH)_{2} + CO_{2} -------->  CaCO_{3} + H_{2} O

From the above equation we can see that the mole ratio of Ca(OH)₂ and CaCO₃ is 1:1 . This can be used as a conversion factor to find moles of CaCO₃ formed during the reaction

2mol[Ca(OH)2] * \frac{1mol[CaCO3]}{1mol[Ca(OH)2]} = 2 mol [CaCO3]

Using molar mass of CaCO3 ( MW = 100.1 g/mol) we can convert moles of CaCO3 to grams.

2mol[CaCO3] * \frac{100.1g[CaCO3]}{1mol[CaCO3]} = 200.2g[CaCO3]

200.2 grams of the precipitate will be produced.

7 0
4 years ago
How many moles of mercury are produced if 74g of oxygen are produced
Maurinko [17]
<span>4.6 moles Hg should be the answer. Hope this helps!</span>
6 0
3 years ago
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