Grams of CuCI please help 10 point

Serga [27]

It is very important to know the shape of a molecule if one is to understand its reactions. It is also desirable to have a simple method to predict the geometries of compounds. For main group compounds, the VSEPR method is such a predictive tool and unsurpassed as a handy predictive method.

7 0

2 years ago

Read 2 more answers

What is the period number of krypton

RUDIKE [14]

The period number of krypton is 4

4 0

2 years ago

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PLEASE HELP ME !!!!

labwork [276]

Answer:

electrons..............

3 0

2 years ago

Which of the following is NOT a postulate of the Kinetic Molecular Theory?

kotegsom [21]

Answer:

"3. Energy can either be destroyed or created. Its goes from one form to another."

Explanation:

The third answer choice, "3. Energy can either be destroyed or created. Its goes from one form to another. " is related to the Law of Conservation of Energy from thermodynamics. Is it not a postulate of the Kinetic Molecular Theory.

"1. Average Kinetic Energy of the system is a measure of the temperature of the system."

Postulate of Kinetic Molecular Theory $\checkmark$

The average kinetic energy of the system is measured by its temperature and nothing else

"2. Energy is conserved in the collisions between gas molecules.."

Postulate of Kinetic Molecular Theory $\checkmark$

All collisions between gas molecules are perfectly elastic, meaning no energy is lost

"3. Energy can either be destroyed or created. Its goes from one form to another.

$\times$ NOT a Postulate of Kinetic Molecular Theory

Related to Conservation of Energy from thermodynamics

"4. Gases travel in straight line until they collide with other gas molecules"

Postulate of Kinetic Molecular Theory $\checkmark$

All gas molecules will travel in a straight line until they collide with other gas molecules or some object (e.g. a container)

8 0

2 years ago

ou will prepare 250-mL of this solution using a 30% (m/v) NaOH stock solution. How many mL of the NaOH stock solution will you n

ArbitrLikvidat [17]

Answer:

$\boxed{\text{3.3 mL}}$

Explanation:

You must convert 30 % (m/v) to a molar concentration.

Assume 1 L of solution.

1. Mass of NaOH

$\text{Mass of NaOH} = \text{1000 mL solution } \times \dfrac{\text{30 g NaOH}}{\text{100 mL solution}} = \text{300 g NaOH}$

2. Moles of NaOH

$\text{Moles of NaOH} = \text{300 g NaOH} \times \dfrac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{7.50 mol NaOH}$

3. Molar concentration of NaOH

$c= \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{7.50 mol}}{\text{1 L}} = \text{7.50 mol/L}$

4. Volume of NaOH

Now that you know the concentration, you can use the dilution formula .

$c_{1}V_{1} = c_{2}V_{2}$

to calculate the volume of stock solution.

Data:

c₁ = 7.50 mol·L⁻¹; V₁ = ?

c₂ = 0.1 mol·L⁻¹; V₂ = 250 mL

Calculations:

(a) Convert millilitres to litres

$V = \text{250 mL} \times \dfrac{ \text{1 L}}{\text{1000 mL}} = \text{0.250 L}$

(b) Calculate the volume of dilute solution

$\begin{array}{rcl}7.50V_{1} & = & 0.1 \times 0.250\\7.50V_{1} &= & 0.0250\\V_{1} & = & \text{0.0033 L}\\& = & \textbf{3.3 mL}\\\end{array}$

$\text{You will need $\boxed{\textbf{3.3 mL}}$ of the stock solution.}$

4 0

2 years ago