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wolverine [178]
3 years ago
6

A parachute on a racing dragster opens and changes the speed of the car from 93 m/s to 45 m/s in a period of 5.3 seconds. What i

s the acceleration of the dragster?
Physics
1 answer:
Sidana [21]3 years ago
5 0

Answer:

-9.06\:\mathrm{m/s^2}

Explanation:

We can use the following kinematics equation to solve for acceleration:

v_f=v_f+at.

Solving for a:

45=93+5.3a,\\-48=5.3a,\\a\approx \boxed{-9.06\mathrm{m/s^2}}

*Note: Since acceleration is a vector quantity, it has both magnitude and direction. The negative sign implies that the acceleration is in the opposite direction of the racing dragster's movement.

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A 69.5-kg person throws a 0.0475-kg snowball forward with a ground speed of 31.5 m/s. A second person, with a mass of 57.5 kg, c
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Answer:

- After throwing the snow, velocity of the thrower is 2.33 m/s

- the velocity of the receiver is 0.026 m/s

Explanation:

Given the data in the question;

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161.94035 = mv

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161.94035 = 69.5 × v

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Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s

Next is the Receiver;

the receiver will gain momentum of 1.49625 kg.m/s

he has no momentum initially and after he catches the snow ball;

1.49625 kg.m/s = mv

1.49625 kg.m/s = ( 57.5 kg +  0.0475 kg ) × v

1.49625 kg.m/s = 57.5475 kg × v

v = ( 1.49625 kg.m/s ) / 57.5475 kg

v = 0.026 m/s

Therefore, the velocity of the receiver is 0.026 m/s

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