I need help solving both of the questions fast please!!!!!!

Physics

1 answer:

sergey [27]2 years ago

6 0

I haven´t learned that yet I´m sorry.

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As food passes through the alimentary canal, the presence of chemical secretions will occur in which order?

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The planet Jupiter has an acceleration due to gravity that is approximately 2.4 times as much as the earth (23.2 m s2 ). Which o

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On Jupiter, C. your weight would increase by a factor of 2.4 . Weight is a product of mass and gravity. Mass does not change dependent upon location.

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The event in the life of a star that begins its expansion into a giant is Group of answer choices almost all the hydrogen in its

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The event in the life of a star that begins its expansion into a giant is its core that was hot enough for fusion reaction.

<h3>What is fusion reaction?</h3>

Nuclear fusion is a type of reaction in which two or more atomic nuclei are fuse to form one or more different atomic nuclei with the release or the absorption of energy.

So we can conclude that the event in the life of a star that begins its expansion into a giant is its core that was hot enough for fusion reaction.

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1 year ago

A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begin

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Part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
$W= \int\limits^{0.540m}_{0} {F} \, dx = \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx =$
$=16000x+10000 \frac{x^2}{2} - 26000 \frac{x^3}{3}$
By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
$W=16000(0.540m)+10000 \frac{(0.540m)^2}{2} - 26000 \frac{(0.540m)^3}{3} =$
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part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
$W=16000(0.95m)+10000 \frac{(0.95m)^2}{2} - 26000 \frac{(0.95m)^3}{3} =$
$=12280 J=12.28 kJ$

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How far should pencil held from a convex mirror of radius 80 cm to form an image one-half the size of the pencil?

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Answer:

10.0

Explanation:

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