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2 years ago

Find the slope of the line through each pair of points. (-10, -10), (5,8)

Mathematics

1 answer:

Rufina [12.5K]2 years ago

7 0

Answer:

i think the answer is 6/5

Step-by-step explanation:

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F(x)=-4x^2+10x-8

vazorg [7]

Answer:

Step-by-step explanation:

a = - 4

b = 10

c = - 8

The discriminate is

D = b^2 - 4ac

D = 10^2 - 4*(-4)(-8)

D = 100 - 128

D = - 28 which is not a nice number

Because the Discriminate has a minus result, there are no real zeros.

6 0

3 years ago

My car gets 34 miles per gallon at 60 miles per hour. Is the number of miles I can drive at 60 miles per hour a linear function

Assoli18 [71]

Answer: Yes,

Step-by-step explanation: If you have less than 60 miles in your gas tank it will not last 1 hour.

7 0

2 years ago

The veterinarian weighed Oliva's new puppy, Benz, on a defective scale.

Mrrafil [7]

Answer:

$\boxed{x = 10.28 \%}$

Step-by-step explanation:

$\frac{(26.75)x}{100} = 2.75 \\ \boxed{x = 10.280373832}$

5 0

2 years ago

The ages of the Oscar-winners for best actor and actress for the years 1970 through 1990 are given below: Women: 34, 34,26,37,42

Artemon [7]

Answer:

See explanation below.

Step-by-step explanation:

Numerical way

We can calculate the mean and the standard deviation from a sample with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

We have the following dataset for women: 34,34,26,37,42,41,35,31,41,33,30,74,33,49,38,61,21,41,26,80,72

And the mean and deviation are:

$\bar X_F = 41.857$

$s_F = 16.399$

We can calculate the median ordering the data like this:

21,26,26,30,31,33,33,34,34,35,37,38,41,41,41,42,49,61,72,74,80

And the median would be on the 11 position of the data ordered, for this case is:

$median_F = 37$

$Minimum_F = 21 , Maximum_F = 80$

And the range is given by: $Range_F = 80-21=59$

We can also calculate the coefficient of variation given by:

$\hat{CV} =\frac{s}{\bar X} = \frac{16.399}{41.857}=0.392$

We have the following dataset for men:

43, 40,48,48,56,38,60,32,40,42,37,76,39,55,45,35,61,33,51,32,42

And the mean and deviation are:

$\bar X_M = 45.381$

$s_M = 11.218$

We can calculate the median ordering the data like this:

32, 32,33,35,37,38,39,40,40,42,42,43,45,48,48,51,55,56,60,61,76

And the median would be on the 11 position of the data ordered, for this case is:

$median_M = 42$

$Minimum_M = 32 , Maximum_F = 76$

And the range is given by: $Range_M = 76-32=44$

We can also calculate the coefficient of variation given by:

$\hat{CV} =\frac{s}{\bar X} = \frac{11.218}{45.381}=0.247$

We se that the mean for the male groups is higher than the mean for female group. The deviation is higher for the female group comapred to the male group. We have more variation for the female group as we can see on the range and the coeffcient of variation.

Graph

We can see the histograms for each group on the figures attached.

As we can see the histogram for males is skewed to the right with the median lower than the mean.

By the other hand the histogram for the female group seems to be skewed to the right also but with missing values on the interval 50-60, for this reason we have more variation compared to the male group.

7 0

3 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

3 years ago

Find the slope of the line through each pair of points. (-10, -10), (5,8)​

Find the slope of the line through each pair of points. (-10, -10), (5,8)