All categories

3 years ago

When equilibrium is reached in an electrochemical cell, the voltage reaches its maximum value. 1. false 2. true?

Physics

2 answers:

tigry1 [53]3 years ago

7 0

False

Voltage in an electrochemical cell is in indication of equilibrium, higher will be the non-equilibrium, higher will be the voltage, or we can say at equilibrium voltage tends to 0.

Voltage in an electrical cell is the result of flow of electron, which flow due to difference in charge of the cells, higher the charge difference higher will be the voltage, as the equilibrium between the chemical cells established the flow of electron will stop, and the voltage of the cell tend to 0.

WITCHER [35]3 years ago

7 0

Answer: The given statement is false.

Explanation:

Voltage in an electrochemical cell helps in determining that the system is out of equilibrium.

When a redox reaction approaches towards equilibrium then there occurs flow of electrons with the advancement in chemical reaction. This means as the chemical reaction proceeds towards completion then flow of electrons also takes place.

Hence, cell potential decreases until the reaction reaches at equilibrium where, $\Delta G$ = 0.

Also, $\Delta G = -nFE$ . So, at equilibrium voltage becomes equal to zero and current also stops.

Thus, we can conclude that the statement when equilibrium is reached in an electrochemical cell, the voltage reaches its maximum value is false.

You might be interested in

A train moving at a constant speed is passing a stationary observer on a platform. On one of the train cars, a flute player is c

Ilya [14]

Answer:

Explanation:

We shall apply the formula of Doppler effect here

F( APPARENT) = F( REAL ) X V/(V + Vs) [ v is velocity of sound and Vs is velocity of source.

415 = 440 X 343/343+Vs

142345 + 415Vs = 150920

415 V₀ = 8575

V₀ = 20.66 m/s.

8 0

3 years ago

13. If you have a 12 kg object, how do you find the weight?

Leto [7]

The weight is the force of gravity acting on the object. So assuming it’s on earth, 12(9.81) also, F(weight in Newtons)=mass( in kg)acceleration (due to gravity)

5 0

3 years ago

What is the bicyclist's velocity at t=35s?

dlinn [17]

Since we are talking about the relation between the velocity and the time, the distance must be given.
Since no distance is given here, then I'll just tell you how to solve this question in terms of equations and you can substitute with the numbers you have.

The velocity can be calculated using the following rule:
velocity = distance / time
we are given the time as 3.5 seconds, therefore:
velocity = distance / 3.5

5 0

3 years ago

Max (15 kg) and Maya (12 kg) are ice-skating on a frozen pond. At one moment, when Max is skating away from the shore at 8.2 m/s

MaRussiya [10]

Answer:

a) Max’s velocity after their collision = 1.8 m/s away from the shore

b) The snowball was moving 18 m/s

c) Maya threw the snowball with a velocity of 20 m/s at max

Explanation:

<em>1) Max (15 kg) and Maya (12 kg) are ice-skating on a frozen pond. At one moment, when Max is skating away from the shore at 8.2 m/s and Maya is skating towards the shore at 4.6 m/s, they collide and bounce off each other without falling. If Maya rebounds at 3.4 m/s, what is Max’s velocity after their collision?</em>

m1*v1 +m2*V2 = m1*V1+m2+V2

⇒ with m1 = mass of max

⇒ with v1 = speed max is skating away = 8.2 m/s

⇒ with m2 = mass of Maya

⇒ with v2 = speed towards the shore Maya = -4.6 m/s

⇒ with V1 = Max's veocity after the collision

⇒ with V2 = Maya's velocity after the collision = 3.4 m/s

Maya has a negative velocity before collision, because she is coming from the opposite direction. Her velocity after collision is positive because she rebounded, which means she went backwards, following the direction Max was coming from.

15kg * 8.2m/s + 12kg * -4.6m/s = 15kg * V1 + 12kg * 3.4m/s

67.8 = 15V1 + 40.8

27 = 15V1

V1 = 1.8 m/s

Max’s velocity after their collision = 1.8 m/s away from the shore

<em />

<em>2) Max (15 kg) and Maya (12 kg) are ice-skating on a frozen pond. When Max is standing on the shore, he throws a 1.5-kg snowball at Maya, who is standing at the center of the pond. Maya catches the snowball and she and the snowball move away from the shore at 2.0 m/s. How fast was the snowball moving right before Maya caught it?</em>

<em> </em>

Let's consider away from Max as positive.

M1*v1 = (M1 +m2)*v2

⇒ with M1 = the mass of the snowball = 1.5 kg

⇒ with v1 = the velocity

⇒ with m2 = the mass of Maya = 12 kg

⇒ with v2 = velocity of Maya and the snowball = 2.0 m/s

1.5kg * v1 = (1.5 + 12)kg * 2m/s

1.51*v1 = 27

v1 = 18 m/s

The snowball was moving 18 m/s

<em>Max (15 kg) and Maya (12 kg) are ice-skating on a frozen pond. While standing at the center of the pond, Maya throws a 1.5-kg snowball at Max and, as a result, recoils away from Max at 2.5 m/s. With what speed did Maya throw the snowball at Max?</em>

Consider the direction 'to Max' as positive and away from Max as negative.

m1*v1 + m2*v2 = 0

⇒ with m1 = the mass of Maya = 12 kg

⇒ with v1 = the velocity of Maya = -2.5 m/s

⇒ with m2 = thz mass of the snowball = 1.5 kg

⇒ with v2 = the velocity of the snowball

12kg * -2.5m/s + 1.5kg * V =0

-30 = -1.5V

V = 20 m/s

Maya threw the snowball with a velocity of 20 m/s at max

7 0

4 years ago

PLEASE HELP ASAP:

antoniya [11.8K]

True since coulomb's law states that There is electric force between like charges or opposite charges. The negative sign only shows the nature of the force.

<h3>What is the coulombs law ?</h3>

coulombs formula is given by

$F= \dfrac{K\times q_{1} \times q_{2}}{r^{2} }$

Now it states that if two charged particles are separated by the distance r and having same or opposite charge will attract or repel each other.

The intensity of the force depend upon the distance and the nature of the charge.

Hence coulomb's law states that There is electric force between like charges or opposite charges. The negative sign only shows the nature of the force.

To know more about coulomb's law follow

https://brainly.in/question/332179

8 0

3 years ago

Read 2 more answers