The complete question is;
A circular coil consists of N = 410 closely winded turns of wire and has a radius R = 0.75 m. A counterclockwise current I = 2.4 A is in the coil. The coil is set in a magnetic field of magnitude B = 1.1 T.
a. Express the magnetic dipole moment μ in terms of the number of the turns N, the current I, and radius
R.
b. Which direction does μ go?
Answer:
A) μ = 1738.87 A.m²
B) The direction of the magnetic moment will be in upward direction.
Explanation:
We are given;
The number of circular coils;
N = 410
The radius of the coil;R = 0.75m
The current in the coils; I = 2.4 A
The strength of magnetic field;
B =1.1T
The formula for magnetic dipole moment is given as;
μ = NIA
Where;
N is number of turns
I is current
A is area
Now, area; A = πr²
So, A = π(0.75)²
Thus,plugging in relevant values, the magnetic dipole moment is;
μ = 410 * 2.4 * π(0.75)²
μ = 1738.87 A.m²
B) According to Fleming's right hand rule, the direction of the magnetic moment comes out to be in upward direction.
Answer:
The strength of magnetic field is 
T
Explanation:
Given:
Length of rod 
m
Velocity 
Induced emf 
V
According to the faraday's law
Induced emf = 
We have to find strength of the magnetic field,
T
Therefore, the strength of magnetic field is T
Answer:
4523.17365 Pa
Explanation:
m = Mass of plane = 77000 kg
F = Force = Weight = 
g = Acceleration due to gravity = 9.81 m/s²
A = Total area of wings = 167 m²
The pressure difference would be
The pressure difference required to keep the plane aloft is 4523.17365 Pa
The answer to your question will be C. because they are very inexpensive and are readily available but they will eventually deplete because we use them faster than they can be produced we use what has been building up.
