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Alisiya [41]
3 years ago
10

Can someone help me with this question please? I'm confused

Mathematics
1 answer:
Art [367]3 years ago
3 0

Answer:

Try asking your teacher if you don't understand it that well.

Step-by-step explanation:

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Currently, each student in our school system is assigned a 6-digit (each
N76 [4]

Answer:

26,000,000 codes

Step-by-step explanation:

To find how many unique codes can be created, we just need to check how many possibilities there are for each letter or digit in the code.

Each letter has 26 possible values, and each digit has 10 possible values, so as we have 1 letter and 6 digits, the total number of unique codes are:

26 * 10 * 10 * 10 * 10 * 10 * 10 = 26,000,000 codes.

6 0
4 years ago
An aerosol can contains gases under a pressure
slavikrds [6]

Answer:

temperature on the beach = T2 = 34.56 °C

Step-by-step explanation:

We are given;

P1 = 4.5 atm

T1 = 24 °C = 24 + 273 = 297 K

P2 = 4.66 atm

Thus, P1/T1 = P2 /T2

So, T2 = P2•T1/P1

Thus, T2 = (4.66x 297)/4.5

T2 = 307.56 K

Let's convert to °C to obtain ;

T2 = 307.56 - 273

T2 = 34.56 °C

7 0
3 years ago
The doubling period of a bacterial population is 15 minutes. At time t= 80 minutes, the bacterial population was 90000​
Papessa [141]

Answer:

here i finished!

hope it helps yw!

Step-by-step explanation:

The doubling period of a bacterial population is 15 minutes.

At time t = 90 minutes, the bacterial population was 50000.

Round your answers to at least 1 decimal place.

:

We can use the formula:

A = Ao*2^(t/d); where:

A = amt after t time

Ao = initial amt (t=0)

t = time period in question

d = doubling time of substance

In our problem

d = 15 min

t = 90 min

A = 50000

What was the initial population at time t = 0

Ao * 2^(90/15) = 50000

Ao * 2^6 = 50000

We know 2^6 = 64

64(Ao) = 50000

Ao = 50000/64

Ao = 781.25 is the initial population

:

Find the size of the bacterial population after 4 hours

Change 4 hr to 240 min

A = 781.25 * 2^(240/15

A = 781.25 * 2^16

A= 781.25 * 65536

A = 51,199,218.75 after 4 hrs

6 0
3 years ago
The total surface area of a cone whose radius is 2 r and slant height 2l is
vampirchik [111]

Answer:

A=4\pi r(l+r)

Step-by-step explanation:

The total surface area of a cone is given by :

A=\pi rl+\pi r^2\\\\=\pi r(l+r)

Put r = 2r and l = 2l in the above formula

A=\pi \times 2r(2l+2r)\\\\A=2\pi r(2l+2r)\\\\=2\pi r \times 2(l+r)\\\\=4\pi r(l+r)

Hence, the total surface area of the cone is 4\pi r(l+r).

7 0
3 years ago
What is the solution set of the equation?
mihalych1998 [28]
It would be 12 (B)
thats i beleive the answer

4 0
3 years ago
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