Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
Answer:
10
Step-by-step explanation:
Answer:
B: 24ft^2
Step-by-step explanation:
Area of triangle = (base x height)/2
Step 1: form an equation
a = (12ft x 4ft)/2
Step 2: solve equation
a = 48ft^2 / 2
a = 24ft^2
*the base is the measurement for the bottom of a triangle while height is the measurement of the length from the bottom to the top of a triangle*
