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3 years ago

Please help! BRAINLIEST to correct answer!!!!

Chemistry

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Answer:

<h3>Exothermic Process</h3>

Explanation:

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If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount

Schach [20]

<u>Answer:</u> The amount of water required to prepare given amount of salt is 398.4 mL

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.16 M

Given mass of manganese (II) nitrate tetrahydrate = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Putting values in above equation, we get:

$0.16M=\frac{16\times 1000}{251\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{16\times 1000}{251\times 0.16}=398.4mL$

Volume of water = Volume of solution = 398.4 mL

Hence, the amount of water required to prepare given amount of salt is 398.4 mL

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3 years ago

Buddhism was first brought to China via the

Firdavs [7]

Answer:

In the 1800s era

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3 years ago

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A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade

egoroff_w [7]

Answer:

Volume occupied by oxygen gas at 15 degree centigrade is equal to $316.5$ centimeter cube

Explanation:

Assuming Pressure is constant.

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

where T1 and T2 are temperature in Kelvin

Substituting the give values we get-

$\frac{300}{273} = \frac{V_2}{288}$

$V_2 = \frac{288*300}{273} \\V_2 = 316.5$

Volume occupied by oxygen gas at 15 degree centigrade is equal to $316.5$ centimeter cube

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2 years ago

If a cross-country runner covers a distance of 347 meters in 134 seconds what is her speed?

Vlad1618 [11]

Distance s=347 meters
time t=134 sec.
speed =s/t=347/134=2.5896 m/s nearly

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3 years ago

2.40 kJ of heat is added to a slug of platinum and a separate 2.40 kJ of heat is added to a slug of zinc. The heat capacity of t

leonid [27]

Final temperature of platinum :- 36.5°C

Final temperature of Zinc :- 29.17°C

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3 years ago