Answer:
0.014s
Explanation:
Given parameters:
mass of golf ball = 0.059kg
force applied = 290N
velocity = 69m/s
initial velocity = 0m/s
Unknown:
Time of contact = ?
Solution;
We know that momentum is the quantity of motion of body possess;
Momentum = mass x velocity
Momentum = 0.059 x 69 = 4.1kgm/s
Also; impulse is the effect of the force acting on a body;
impulse = force x time = momentum
So;
Force x time = momentum
Time =
=
= 0.014s
Answer:
no answer
Explanation:
the question does not sk what to find
<span>We know , E = kQ/r^2 where q = charge and r is separation between point and point charge.
Now, At P, E= kQ/r^2
Since, Q can't be changed, we can do that by varying r
2E = 2kq/r^2
2E = kq/ (r/ sqrt2)^2
Hence, if we bring Q closer such that distance between P and Q becomes r/ sqrt 2, E will get doubled.</span>
Answer:
I'm pretty sure the answer is runoff