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leva [86]
3 years ago
14

What did Thomson’s model of the atom include that Dalton’s model did not have?

Physics
2 answers:
Lelechka [254]3 years ago
7 0

Answer:

smaller particles

Explanation:

D is the answer

astraxan [27]3 years ago
4 0

Answer: Option (d) is the correct answer.

Explanation:

Dalton's model of atom states that every matter is made up of atoms and these atoms are indivisible in nature.

On the other hand, Thomson's model of atom states that there are small particles present in an atom that has positive or negative charges.

Thomson's model of atom is also known as plum pudding model where negatively charged particles are represented by plum and positively charged particles are represented by pudding.

Thus, we can conclude that Thomson’s model of the atom include smaller particles that Dalton’s model did not have.

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Which of the following would decrease the resistance to the flow of an electric current through a body?
Art [367]
Shortening the conductor (B) <span> would decrease the resistance
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8 0
3 years ago
A 90kg man is standing still on frictionless ice. His friend tosses him a 10kg ball, which has a horizontal velocity of 20m/s. A
Ludmilka [50]
Using the conservation of momentum,
ma*va1 + mb*vb1 = ma*va2 + mb*vb2
Let:
ma = mass of the ball
va = velocity of the ball
mb = mass of the man
vb = velocity of the man
The subscript 1 is known as initials while 2 is for finals.
Before the man throws the ball, he starts at rest, meaning the initial velocity of the ball and the initial velocity of the man are zero. So
0 = ma*va2 + mb*vb2
Given ma = 10 kg; va = 20 m/s; mb = 90 kg; vb is unknown, therefore
-(mb*vb2) = ma*va2
vb2 = -(ma*va2)/mb2 = -(10*20)/90 = -2.22 m/s
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7 0
3 years ago
Read 2 more answers
A frequently quoted rule of thumb in aircraft design is that wings should produce about 1000 N of lift per square meter of wing.
svetlana [45]

Answer:

    v₂ = 63.62 m / s

Explanation:

For this exercise in fluid mechanics we will use Bernoulli's equation

         P₁ + ρ g v₁² +  ρ g y₁ = P₂ +  ρ g v₂² +  ρ g y₂

where the subscript 1 refers to the inside of the wing and the subscript 2 to the top of the wing.

We will assume that the distance between the two parts is small, so y₁ = y₂

        P₁-P₂ =  ρ g (v₂² - v₁²)

pressure is defined by

        P = F / A

we substitute

        ΔF / A =  ρ g (v₂² - v₁²)

         v₂² = \frac{\Delta F}{A \ \rho  \ g} + v_1^2

suppose that the area of ​​the wing is A = 1 m²

we substitute

         v₂² = \frac{1000}{1 \ 1.29 \ 9.8} + 63^2

         v₂² = 79.10 + 3969

         v₂ = √4048.1

         v₂ = 63.62 m / s

7 0
3 years ago
What happens when you combine purple and yellow?
Nana76 [90]
Umm You make brown lol
3 0
3 years ago
If a pulley system with an ideal mechanical advantage of 2,000,000 is used in lifting a 2,000 lb. car, how far would the car mov
krek1111 [17]

Answer:

C

Explanation:

4 0
3 years ago
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