1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
TiliK225 [7]
3 years ago
15

A child threw a stone straight down off a high bridge. The initial velocity of the stone was 15.0 m/s (include units and proper

significant figures). How fast was the stone moving the instant before it hit the river 3.00 sec later?
Physics
1 answer:
Andre45 [30]3 years ago
8 0

Answer:

The speed of the stone before it hit the river 3.00 sec later. Let v is the velocity at that instant is 45 m/s.

Explanation:

Given that, a child threw a stone straight down off a high bridge.

Initial velocity of the stone, u = 15 m/s

We need to find the speed of the stone before it hit the river 3.00 sec later. Let v is the velocity at that instant. When it come down, it is moving under the action of gravity. Using equation of motion as :

v=u+gt\\\\v=15+10\times 3\\\\v=45\ m/s

So, the speed of the stone before it hit the river 3.00 sec later. Let v is the velocity at that instant is 45 m/s.

You might be interested in
Vector A⃗ points in the positive y direction and has a magnitude of 12 m. Vector B⃗ has a magnitude of 33 m and points in the ne
gavmur [86]

vector A has magnitude 12 m and direction +y

so we can say

\vec A = 12 \hat j

vector B has magnitude 33 m and direction - x

\vec B = -33 \hat i

Now the resultant of vector A and B is given as

\vec A + \vec B = 12 \hat j - 33 \hat i

now for direction of the two vectors resultant will be given as

\theta = tan^{-1}\frac{12}{-33}

\theta = 160 degree

so it is inclined at 160 degree counterclockwise from + x axis

magnitude of A and B will be

R = \sqrt{A^2 + B^2}

R = \sqrt{12^2 + 33^2} = 35.11 m

so magnitude will be 35.11 m

6 0
3 years ago
Metals such as aluminum can be formed into thin sheets because they are
Korvikt [17]

Answer:

They are malleable.

Explanation:

Malleability is the property of metals that causes them to be able to be formed into thin sheets without breaking.

All metals are malleable.

The reason why metals are malleable is because the atoms in the metals have a stable structure and hence, when beaten, the atoms can move freely among each other and maintain their structure.

8 0
3 years ago
Read 2 more answers
1L of a solution of oxalic acid [(). ] contains 2.52g of acid.
alexandr1967 [171]

Answer:

0.028 M.

Explanation:

NOTE: This question is a chemistry question. However, the answer to the question can be obtained as shown below:

We'll begin by calculating the number of mole in 2.52 g of oxalic acid, C₂H₂O₄. This can be obtained as follow:

Mass of C₂H₂O₄ = 2.52 g

Molar mass of C₂H₂O₄ = (2×12) + (2×1) + (4×16)

= 24 + 2 + 64

= 90 g/mol

Mole of C₂H₂O₄ =?

Mole = mass / molar mass

Mole of C₂H₂O₄ = 2.52 / 90

Mole of C₂H₂O₄ = 0.028 mole

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of C₂H₂O₄ = 0.028 mole

Volume = 1 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.028 / 1

Molarity = 0.028 M

Therefore, the molarity of the solution is 0.028 M.

5 0
3 years ago
If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.2 ss , how far do you travel during this ina
ICE Princess25 [194]

Answer: 55m

Explanation:

Given the following :

Driving speed = 90km/hr

Inattentive period (time) = 2.2s

Distance during inattentive period =

(driving speed * time)

Converting driving speed from km/hr to m/s

1000m = 1km

3600s = 1hour

Therefore,

90km/hr = (90 * 1000) / 3600

90km/hr = (90000)/ 3600 = 25m/s

Therefore ;

Distance during inattentive period =

(driving speed * time)

Distance during inattentive period = (25m/s × 2.2s) = 55m

Distance traveled during inattentive period is 55m

6 0
3 years ago
Suppose a convex mirror has a focal length of 120 cm. A candle sits directly in front of the mirror. If the image of that candle
Andru [333]
We can solve the problem by using the mirror equation:
\frac{1}{f} = \frac{1}{d_o}+ \frac{1}{d_i}
where
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

For the sign convention, the focal length is taken as negative for a convex mirror:
f=-120 cm
and the image is behind the mirror, so virtual, therefore its sign is negative as well:
d_i=-24 cm
putting the numbers in the mirror equation, we find the distance of the object from the mirror surface:
\frac{1}{d_o} = \frac{1}{f}- \frac{1}{d_i}= \frac{1}{-120 cm} - \frac{1}{-24 cm}= \frac{1}{30 cm}
So, the distance of the object from the mirror is d_o = 30 cm
8 0
3 years ago
Other questions:
  • Which is the correct formula for sulfur dichloride
    8·2 answers
  • A dockworker applies a constant horizontal force of 79.0 N to a block of ice on a smooth horizontal floor. The frictional force
    11·1 answer
  • How is energy related to the change of state represented by the model?
    15·1 answer
  • Are Magnetic force fields are straight lines
    11·1 answer
  • The soccer field is _____.
    13·2 answers
  • Cellular telephones use
    9·2 answers
  • A scientific theory is a well-tested explanation for a wide range of observations or experimental results. A hypothesis is a pos
    14·2 answers
  • What is the gravitational force between two cars (one car is 1500 kg and the other car is 1000 kg) in a parking lot that are thr
    14·1 answer
  • Water pollution can come from the _______ of dead organic matter or animal waste in waterways.
    6·2 answers
  • Forest protect the soil from erosion ? True or False
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!