Answer:
a. A = 0.1656 m
b. % E = 1.219
Explanation:
Given
mB = 4.0 kg , mb = 50.0 g = 0.05 kg , u₁ = 150 m/s , k = 500 N / m
a.
To find the amplitude of the resulting SHM using conserver energy
ΔKe + ΔUg + ΔUs = 0
¹/₂ * m * v² - ¹/₂ * k * A² = 0
A = √ mB * vₓ² / k
vₓ = mb * u₁ / mb + mB
vₓ = 0.05 kg * 150 m / s / [0.050 + 4.0 ] kg = 1.8518
A = √ 4.0 kg * (1.852 m/s)² / (500 N / m)
A = 0.1656 m
b.
The percentage of kinetic energy
%E = Es / Ek
Es = ¹/₂ * k * A² = 500 N / m * 0.1656²m = 13.72 N*0.5
Ek = ¹/₂ * mb * v² = 0.05 kg * 150² m/s = 1125 N
% E = 13.72 / 1125 = 0.01219 *100
% E = 1.219
Gravitational energy is a form of potential energy because it is dependent on the mass of an object and needs to be calculated for the specific object.
Answer:
The shear modulus of the polymer is 5 MPa
Solution:
As per the question:
displacement of the top plate, d = 2 mm = 0.002 m
Horizontal Force, P = 2 kN = 2000 N
Width of the block, w = 100 mm = 0.1 m
By small angle analysis:
Angle, 
Now,
Stress,
= 

Answer:
The answer is A
Explanation:
Being the force is acting upwards and displacement takes place horizontally
Answer:
Friction
Explanation:
The key and most important external forces that allows a man to push a wheelbarrow is frictional force.
Frictional force is a force that opposes motion and will bring it to a halt.
The reason why motion is possible is due to frictional force.
Without friction, a body will move and continue in motion infinitely. No one will be able to control motion.
- Therefore, frictional force is an external force that will allow a man to push a wheelbarrow.