vector A has magnitude 12 m and direction +y
so we can say

vector B has magnitude 33 m and direction - x

Now the resultant of vector A and B is given as

now for direction of the two vectors resultant will be given as


so it is inclined at 160 degree counterclockwise from + x axis
magnitude of A and B will be


so magnitude will be 35.11 m
Answer:
They are malleable.
Explanation:
Malleability is the property of metals that causes them to be able to be formed into thin sheets without breaking.
All metals are malleable.
The reason why metals are malleable is because the atoms in the metals have a stable structure and hence, when beaten, the atoms can move freely among each other and maintain their structure.
Answer:
0.028 M.
Explanation:
NOTE: This question is a chemistry question. However, the answer to the question can be obtained as shown below:
We'll begin by calculating the number of mole in 2.52 g of oxalic acid, C₂H₂O₄. This can be obtained as follow:
Mass of C₂H₂O₄ = 2.52 g
Molar mass of C₂H₂O₄ = (2×12) + (2×1) + (4×16)
= 24 + 2 + 64
= 90 g/mol
Mole of C₂H₂O₄ =?
Mole = mass / molar mass
Mole of C₂H₂O₄ = 2.52 / 90
Mole of C₂H₂O₄ = 0.028 mole
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of C₂H₂O₄ = 0.028 mole
Volume = 1 L
Molarity =?
Molarity = mole / Volume
Molarity = 0.028 / 1
Molarity = 0.028 M
Therefore, the molarity of the solution is 0.028 M.
Answer: 55m
Explanation:
Given the following :
Driving speed = 90km/hr
Inattentive period (time) = 2.2s
Distance during inattentive period =
(driving speed * time)
Converting driving speed from km/hr to m/s
1000m = 1km
3600s = 1hour
Therefore,
90km/hr = (90 * 1000) / 3600
90km/hr = (90000)/ 3600 = 25m/s
Therefore ;
Distance during inattentive period =
(driving speed * time)
Distance during inattentive period = (25m/s × 2.2s) = 55m
Distance traveled during inattentive period is 55m
We can solve the problem by using the mirror equation:

where
f is the focal length

is the distance of the object from the mirror

is the distance of the image from the mirror
For the sign convention, the focal length is taken as negative for a convex mirror:

and the image is behind the mirror, so virtual, therefore its sign is negative as well:

putting the numbers in the mirror equation, we find the distance of the object from the mirror surface:

So, the distance of the object from the mirror is