Answer:
![+1.11\mu C](https://tex.z-dn.net/?f=%2B1.11%5Cmu%20C)
Explanation:
A charge located at a point will experience a zero electrostatic force if the resultant electric field on it due to any other charge(s) is zero.
is located at the origin. The net force on it will only be zero if the resultant electric field intensity due to
and
at the origin is equal to zero. Therefore we can perform this solution without necessarily needing the value of
.
Let the electric field intensity due to
be +
and that due to
be -
since the charge is negative. Hence at the origin;
![+E_2-E_3=0..................(1)](https://tex.z-dn.net/?f=%2BE_2-E_3%3D0..................%281%29)
From equation (1) above, we obtain the following;
![E_2=E_3.................(2)](https://tex.z-dn.net/?f=E_2%3DE_3.................%282%29)
From Coulomb's law the following relationship holds;
![-E_3=\frac{kQ_3}{r_3^2}](https://tex.z-dn.net/?f=-E_3%3D%5Cfrac%7BkQ_3%7D%7Br_3%5E2%7D)
where
is the distance of
from the origin,
is the distance of
from the origin and k is the electrostatic constant.
It therefore means that from equation (2) we can write the following;
![\frac{kQ_2}{r_2^2}=\frac{kQ_3}{r_3^2}.................(3)](https://tex.z-dn.net/?f=%5Cfrac%7BkQ_2%7D%7Br_2%5E2%7D%3D%5Cfrac%7BkQ_3%7D%7Br_3%5E2%7D.................%283%29)
k can cancel out from both side of equation (3), so that we finally obtain the following;
![\frac{Q_2}{r_2^2}=\frac{Q_3}{r_3^2}................(4)](https://tex.z-dn.net/?f=%5Cfrac%7BQ_2%7D%7Br_2%5E2%7D%3D%5Cfrac%7BQ_3%7D%7Br_3%5E2%7D................%284%29)
Given;
![Q_2=?\\r_2=2.5cm=0.025m\\Q_3=-2.18\mu C=-2.18* 10^{-6}C\\r_3=3.5cm=0.035m](https://tex.z-dn.net/?f=Q_2%3D%3F%5C%5Cr_2%3D2.5cm%3D0.025m%5C%5CQ_3%3D-2.18%5Cmu%20C%3D-2.18%2A%2010%5E%7B-6%7DC%5C%5Cr_3%3D3.5cm%3D0.035m)
Substituting these values into equation (4); we obtain the following;
![\frac{Q_2}{0.025^2}=\frac{2.18*10^{-6}}{0.035^2}\\\\hence;\\\\Q_2=\frac{0.025^2*2.18*10^{-6}}{0.035^2}\\](https://tex.z-dn.net/?f=%5Cfrac%7BQ_2%7D%7B0.025%5E2%7D%3D%5Cfrac%7B2.18%2A10%5E%7B-6%7D%7D%7B0.035%5E2%7D%5C%5C%5C%5Chence%3B%5C%5C%5C%5CQ_2%3D%5Cfrac%7B0.025%5E2%2A2.18%2A10%5E%7B-6%7D%7D%7B0.035%5E2%7D%5C%5C)
![Q_2=\frac{0.00136*10^{-6}}{0.00123}=1.11*10^{-6}C\\\\Q_3=+1.11\mu C](https://tex.z-dn.net/?f=Q_2%3D%5Cfrac%7B0.00136%2A10%5E%7B-6%7D%7D%7B0.00123%7D%3D1.11%2A10%5E%7B-6%7DC%5C%5C%5C%5CQ_3%3D%2B1.11%5Cmu%20C)
Answer:
Weight
Explanation:
Weight is the downward pull on an object due to gravity.
For example, the moon has less gravity than Earth so we would weigh less on the moon. Our Mass and volume always stay the same but our weight could change.
The volume of water will increase . If yu subtract the original volume from the new volume of water you will get the volume of the small ball.