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3 years ago

9

i tryied to get the whole thing on but tht works but pls answer this for me befor my dad gets home he wants me to be done for th

e whole school year by tomorrow

2 answers:

RoseWind [281]3 years ago

5 0

Answer:

3

Step-by-step explanation:

Viktor [21]3 years ago

3 0

Answer:

a

Step-by-step explanation:

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Reduce the following fraction: -36x^4y^4z^5/-12x^6y^3z

Evgesh-ka [11]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{-36x^4y^4z^5}{-12x^6y^3z}\quad 
\begin{cases}
36=2\cdot 2\cdot 3\cdot 3\\
12=2\cdot 2\cdot 3
\end{cases}\implies \cfrac{-36}{-12}\cdot \cfrac{x^4y^4z^5}{x^6y^3z^1}
\\\\\\
\cfrac{\underline{-2\cdot 2\cdot 3}\cdot 3}{\underline{-2\cdot 2\cdot 3}}\cdot \cfrac{x^4y^4z^5x^{-6}y^{-3}z^{-1}}{1}\implies \cfrac{3}{1}\cdot 
\cfrac{x^4x^{-6}y^4y^{-3}z^5z^{-1}}{1}$

$\bf \cfrac{3}{1}\cdot \cfrac{x^{4-6}y^{4-3}z^{5-1}}{1}\implies 
\cfrac{3}{1}\cdot\cfrac{x^{-2}y^{1}z^4}{1}\implies 
\cfrac{3x^{-2}yz^4}{1}\implies \cfrac{3yz^4}{x^2}$

6 0

3 years ago

Consider the polar curve r = 4sin(2θ). What is the length of each petal, and how many petals does the graph have?

sdas [7]

Answer:

The length of each pearl is a given r= a cos(n 0) the answer is 4 and number of petals is 4 (I think )

Step-by-step explanation:

7 0

3 years ago

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Can you help me with this question?

Bond [772]

SAS, side angle side congruency

4 0

3 years ago

Jen and ted have cookies for snack time. Jen has 4 cookies. Ted has 1 less cookie than Jen. How many cookies does ted have

algol13

The answer for this problem is 3

5 0

3 years ago

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(8CQ) Find the sum of the geometric series. <br> 20-10+5-5/2+...

Ivahew [28]

Answer:

b. $\frac{40}{3}$

Step-by-step explanation:

The given geometric series is;

$20-10+5-\frac{5}{2}+...$

The first term of this series is

$a_1=20$

The common ratio is

$r=\frac{-10}{20}=-\frac{1}{2}$

The sum to infinity of this series is

$S_{\infty}=\frac{a_1}{1-r}$

Substitute the given values to obtain;

$S_{\infty}=\frac{20}{1--\frac{1}{2}}$

This implies that;

$S_{\infty}=\frac{20}{\frac{3}{2}}$

$S_{\infty}=\frac{40}{3}$

8 0

3 years ago

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