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Lunna [17]
3 years ago
11

What are the independent and dependent variables?

Physics
1 answer:
34kurt3 years ago
5 0
The independent variables would be time and he dependent variables would be the distance traveled. Time is always independent because it is not reliant on something else when something happens over a period of time.
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Density is a property of matter that relates
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Density is the mass of a substance per unit volume.
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An object weighs 39.36 newtons. What is its mass if a gravitometer indicates that g = 9.83 m/s2?
CaHeK987 [17]
The force applied to an object is said to be a product of its mass and the acceleration. For this case, acceleration is the reading on the gravitometer. We calculate as follows:

F = mg
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Hope this answers the question. Have a nice day.
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3 years ago
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What is the impulse of a 2 kg object that starts at 10 m/s and comes to a stop over 0.4 seconds?
gizmo_the_mogwai [7]

Answer: Impulse = 20 Ns

Explanation:

Impulse is the product of force and time

Also impulse = momentum

Where momentum is the product of mass and velocity.

Given that

M = 2kg

V = 10 m/s

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8 0
3 years ago
A couple of astronauts agree to rendezvous in space after hours. Their plan is to let gravity bring them together. She has a mas
Oduvanchick [21]

Answer:

(a) Acceleration of female astronaut = 9.33*10^-12 m/s^2; Acceleration of male astronaut = 7.56*10^-12 m/s^2

(b) 27.013 days

(c) No, their accelerations would not be constant.

Explanation:

In the given question, we have:

Mass of female astronaut M_{1} = 60.0 kg

Mass of male astronaut M_{2} = 74.0 kg

Distance between them (S) = 23.0 m

(a) The free-body diagram is shown in the attached figure.

Using the equations below, the initial accelerations of the two astronauts can be calculated:

Force of gravity (F) = \frac{G*M_{1}*M_{2}}{S^{2} }

G = 6.67*10^-11 \frac{m^{3} }{kg*s^{2} }

F = (6.67*10^-11 *60*74)/23^2 = 5.598*10^-10 N

For the female astronaut, her initial acceleration = F/M_{1} = 5.598*10^-10/60 = 9.33*10^-12 m/s^2

For the male astronaut, his acceleration = F/M_{2} = 5.598*10^-10/74 = 7.56*10^-12 m/s^2

(b) Since the different between their mass is not much, we can deduce that:

a_{average} = \frac{a_{1}+a_{2}}{2} = (9.33*10^-12 + 7.56*10^-12)/2 = 8.445*10^-12 m/s^2

Using the equation below, we can calculate the the time:

S = ut + 1/2 (at^2)   where u = 0

23 = 1/2 (8.445*10^-12)*t^2

t^2 = 5.447*10^12

t = 2333883.044 s = 27.013 days

(c) No, their accelerations will not be constant. It will increase because their radii would be decreasing.

8 0
3 years ago
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