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3 years ago

Which form of energy does a plant store when light is transformed during photosynthesis?

2 answers:

7 0

The answer is a. Chemical energy.

Photosynthesis is a process in plants wherein light energy is converted to chemical energy, which is then stored as glucose. This is stored in the chloroplasts.

Photosynthesis is divided into two stages: the light and dark stage. In the light stage, the light energy is converted into ATP and NADPH, these are like the energy cells of the plant. After the light stage, the ATP and NADPH that were produced are used in the dark stage. The dark stage will use these energy cells to transform carbon dioxide into sugar.

Ilya [14]3 years ago

5 0

Answer:

Therefore, a. chemical energy plant store when light is transformed during photosynthesis.

Explanation:

Photosynthesis is the process plants and some algae use to convert light energy to chemical energy stored as sugar within chloroplasts .

Photosynthesis is 6CO2 + 6H20 + light energy = glucose + 6 oxygen.

Photosynthesis is divided into two main stages: light reaction and dark reaction. The light reaction converts light energy into adenosine triphosphate,

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What is the equation: If F=10 N, a=5 m/s², m=?

Romashka-Z-Leto [24]

Answer:

2 kg

Explanation:

Remember:

F = m * a re-arrange to

F/a = m substitute in the given values

10 / 5 = 2 kg

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2 years ago

If you push any floating object down from equilibrium and release it, it bobs up and down. That looks like an oscillation, so le

GarryVolchara [31]

Answer:

$F_{y}$ = ( ρ_fluid g A) y

Explanation:

This exercise can be solved in two parts, the first finding the equilibrium force and the second finding the oscillating force

for the first part, let's write Newton's equilibrium equation

B₀ - W = 0

B₀ = W

ρ_fluid g V_fluid = W

the volume of the fluid is the area of the cube times the height it is submerged

V_fluid = A y

For the second part, the body introduces a quantity and below this equilibrium point, the equation is

B - W = m a

ρ_fluid g A (y₀ + y) - W = m a

ρ_fluid g A y + (ρ_fluid g A y₀ -W) = m a

ρ_fluid g A y + (B₀-W) = ma

the part in parentheses is zero since it is the force when it is in equilibrium

ρ_fluid g A y = m a

this equation the net force is

$F_{y}$ = ( ρ_fluid g A) y

we can see that this force varies linearly the distance and measured from the equilibrium position

8 0

3 years ago

Suppose that a balloon is being filled with air at a rate of 10 cm3/s. (Assume that theballoon is a perfect sphere.) At what rat

Basile [38]

Answer:

Therefore the surface area of the balloon is increased at 4 cm³/s.

Explanation:

The balloon is being filled with air at a rate of 10 cm³/s

It means the volume of the balloon is increased at a rate 10 cm³/s.

i.e $\frac{dv}{dt} =10 cm^3/s$

Consider r be the radius of the balloon.

The volume of of a sphere is

$v=\frac{4}{3} \pi r^3$

Differentiate with respect to t

$\frac{dv}{dt} =\frac{4}{3} \pi \times 3r^2\frac{dr}{dt}$

$\Rightarrow 10 =4\pi r^2\frac{dr}{dt}$

$\Rightarrow \frac{dr}{dt}=\frac{10}{4\pi r^2}$

The surface of area of the balloon is(S) = $4\pi r^2$

$S=4\pi r^2$

Differentiate with respect to t

$\frac{dS}{dt} =4\pi\times2r\frac{dr}{dt}$

$\Rightarrow \frac{dS}{dt} =8\pi r\frac{dr}{dt}$

Putting the value of $\frac{dr}{dt}$

$\Rightarrow \frac{dS}{dt} =8\pi r\times\frac{10}{4\pi r^2}$

$\Rightarrow \frac{dS}{dt} =\frac{20}{ r}$

Given that r = 5 cm

$[\frac{dS}{dt}]_{r=5} =\frac{20}{ 5}$ =4 cm³/s

Therefore the surface area of the balloon is increased at 4 cm³/s.

5 0

4 years ago

Match the vocabulary terms to their definitions.

Vilka [71]

See the attached picture:

8 0

3 years ago

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Cavity wall insulation costs £240 but will save you £32 each year. What is the payback time for cavity

likoan [24]

Answer:

Thus, the payback time for cavity wall insulation is 7.5 years

5 0

2 years ago