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timofeeve [1]
3 years ago
10

What additional information do you need to prove ∆ABC ≅ ∆DEF by the SAS Postulate?

Physics
1 answer:
miv72 [106K]3 years ago
6 0

Answer:

Option A

You need a Angle C congruent to angle F

Explanation:

EX) Side angle Side = sas

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FrozenT [24]

Answer: <u><em>D a source of electricity</em></u>

Explanation: I have done that question please tell me if it is correct

5 0
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Coin-shaped compartment that contains light-absorbing molecules
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Coin-shaped compartment that contains light-absorbing molecules - Thylakoid

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What is the kinetic energy of a 1.0-kg billiard ball that moves at 5.0 m/s?
romanna [79]
K=1/2(mass)(velocity)^2
Mass=1.0
Velocity=5.0
K=1/2(1)(5)^2
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3 0
3 years ago
La superficie de unas botas suman 400 cm2 y la persona que las usa tiene 45 kg de masa, calcula la presión que ejerce sobre el p
liubo4ka [24]

Answer:

11025 N / m²

Explanation:

Los siguientes datos se obtuvieron de la pregunta:

Área (A) = 400 cm²

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Presión (P) =?

A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:

Masa (m) = 45 Kg

Aceleración por gravedad (g) = 9,8 m / s²

Fuerza (F) =.?

F = m × g

F = 45 × 9,8

F = 441 N

A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:

1 cm² = 0,0001 m²

Por lo tanto,

400 cm² = 400 cm² × 0,0001 m² / 1 cm²

400 cm² = 0,04 m²

Por tanto, 400 cm² equivalen a 0,04 m².

Finalmente, determinaremos la presión ejercida de la siguiente manera:

Área (A) = 0.04 m².

Fuerza (F) = 441 N

Presión (P) =?

P = F / A

P = 441 / 0,04

P = 11025 N / m²

Por tanto, la presión ejercida es 11025 M / m²

4 0
3 years ago
For installation with a 25-kVA, 3-phase transformer, a 440-volt primary, and a 120-volt secondary. Calculate the maximum overcur
andre [41]

Answer:

41.053 A

Explanation:

given,

three phase kVA = 25-kVA

voltage = 440 Volt

current = ?

To determine three phase kVA when volts and amperes are know

   three phase kVA = 1.73 x V x I

    I = \dfrac{three\ phase\ kVA}{1.73 \times V}

    I = \dfrac{25000}{1.73 \times 440}

           I = 32.84 A

the maximum overcurrent protection value is equal to

            = 125 % of I

            = 1.25 x 32.84

            = 41.053 A

4 0
3 years ago
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