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k0ka [10]
3 years ago
14

Help pls due in 5 minutes

Mathematics
2 answers:
34kurt3 years ago
7 0

Answer:

4th option

Step-by-step explanation:

5\frac{1}{2}*1 \frac{2}{5}=\frac{11}{2} *\frac{7}{5}  =\frac{77}{10}=7\frac{7}{10}

yaroslaw [1]3 years ago
4 0

Answer:

the answer to this is 7 7/10

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Given p = 4, q = -2, a = 3, the quadratic will look like this:
y = 3(x-4)(x+2)
Finally, distribute and combine like terms to put it in standard form.
y = 3(x^2 - 4x+2x -8) \\  \\ y = 3(x^2 -2x-8) \\  \\ y = 3x^2 -6x -24
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The Halloways are taking a trip to Maine. Mr. Halloway knows that it is about 885 miles to their destination in Maine from their
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Answer:

Number of hours= 13.61 hours

Step-by-step explanation:

Giving the following information:

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3 years ago
Solve the compound inequality |3x-9|≤15 and |2x-3|≥5. Give answer in interval notation.
laila [671]

Answer:

The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is  (-∞,2] ∪ [8,∞)

Step-by-step explanation:

When solving absolute value inequalities, there are two cases to consider.

Case 1: The expression within the absolute value symbols is positive.

Case 2: The expression within the absolute value symbols is negative.

The solution is the intersection of the solutions of these two cases.

In other words, for any real numbers a and b,

  • if |a|> b then a>b or a<-b
  • if |a|< b then a<b or a>-b

So, being |3x-9|≤15

Solving: 3x-9 ≤ 15

3x ≤15 + 9

3x ≤24

x ≤24÷3

x≤8

or 3x-9 ≥ -15

3x ≥-15 +9

3x ≥-6

x ≥ (-6)÷3

x ≥ -2

The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]

So, being |2x-3|≥5

Solving: 2x-3 ≥ 5

2x ≥ 5 + 3

2x ≥8

x ≥8÷2

x≥8

or 2x-3 ≤ -5

2x ≤-5 +3

2x ≤-2

x ≤ (-2)÷2

x ≤ -2

Expressing the solution as an interval: (-∞,2] ∪ [8,∞)

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3 years ago
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