Newtons _ law of motion states that every action has an equal and opposite reaction

a person was using a spanner to loosen a tight nut.Their mass was 50kg the spanner was 0.5m long i) what is the persons weight?

sineoko [7]

1) Weight of the person: 490 N

2) Maximum torque: 245 Nm

Explanation:

1)

The weight of a body is equal to the gravitational force exerted on the body; it is given by the equation

$F=mg$

where

m is the mass of the body

g is the acceleration due to gravity

For the person in this problem,

m = 50 kg is the mass

$g=9.8 m/s^2$ is the acceleration due to gravity on Earth's surface

Therefore, the weight of the person is

$F=(50)(9.8)=490 N$

2)

The turning force (also called torque) exerted by a force rotating an object is given by

$\tau = Fd sin \theta$

where

F is the magnitude of the force

d is the length of the arm (the distance between the force and the pivotal point)

$\theta$ is the angle between the direction of the force and the arm

For the spanner in this problem,

F = 490 N is the force applied (the weight of the person)

d = 0.5 m is the arm (the length of the spanner)

The maximum torque is obtained when $\theta=90^{\circ}$ , therefore it is:

$\tau=(490)(0.5)(sin 90^{\circ})=245 N\cdot m$

Learn more about weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

About torque:

brainly.com/question/5352966

#LearnwithBrainly

5 0

3 years ago

Steam at 0.6 MPa, 200 oC, enters an insulated nozzle with a velocity of 50 m/s. It leaves at a pressure of 0.15 MPa and a veloci

Rudiy27

Answer:

x2 = 0.99

Explanation:

from superheated water table

at pressure p1 = 0.6MPa and temperature 200 degree celcius

h1 = 2850.6 kJ/kg

From energy equation we have following relation

$\dot m( h1+\frac{v1^2}{2}+ gz1 )+ Q = \dot m( h2+\frac{v2^2}{2}+ gz1) + W$

$\dot m( h1+\frac{v1^2}{2}) = \dot m( h2+\frac{v2^2}{2})$

$h1+\frac{v1^2}{2} = h2+\frac{v2^2}{2}$

$2850.6 + [\frac{50^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}] = h2 +[ \frac{600^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}]$

h2 = 2671.85 kJ/kg

from superheated water table

at pressure p2 = 0.15MPa

specific enthalpy of fluid hf = 467.13 kJ/kg

enthalpy change hfg = 2226.0 kJ/kg

specific enthalpy of the saturated gas hg = 2693.1 kJ/kg

as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have

quality of steam x2

h2 = hf + x2(hfg)

2671.85 = 467.13 +x2*2226.0

x2 = 0.99

6 0

3 years ago

Pls help urgent Refer to the image for question

Temka [501]

Answer:

C

Explanation:

Most probable exchange of ions occurs for option C.

3 0

3 years ago

Which item contains a switch that opens when the current in a circuit is too high?

lana [24]

it is circuit breaker

3 0

3 years ago

Read 2 more answers

You have a 1 W light bulb in your lab. It puts out light of only 1 frequency. The wavelength of this light is 500nm. you set up

ollegr [7]

Answer:

a) # _photon = 2.5 10¹⁸ photons / s, b) E = 10⁻² N / C, c) B = 3 10⁻¹¹ T

d) r= 2 10⁹ m

Explanation:

a) Let's solve this exercise in part, let's start by finding the energy of each photon using the Planck relation

E₀ = h f

c = λ f

E₀ = h c /λ

E₀ = 6.63 10⁻³³⁴ 3 10⁸/500 10⁻⁹

E₀ = 3.978 10⁻⁻¹⁹ J

Let's use a direct ratio rule to find the number of photons

#_foton = E / Eo

#_fototn = 1 / 3.978 10⁻¹⁹

# _photon = 2.5 10¹⁸ photons / s

b) The intensity received by the detector is related to the electric field

I = E²

Let's look for the intensity that the detector receives, suppose that the emission is shapeless throughout the space

I = P / A

P = I A

Let's use index 1 for the point on the bulb and index 2 for the point on the detector.

The area of a sphere is

A = 4π r²

P = I₁ A₁ = I₂ A₂

I₁ r₁² = I₂ r₂²

I₂ = I₁ r₁²/r₂²

I₂ = I₁ 1 / 100²

I₂ = I₁ 10⁻⁴

we must know the intensity at the output of the bulb suppose that I₁ = 1 J

I₂ = 10⁻⁴ J

let's look for the electric field

E =√I

E = √10⁻⁴

E = 10⁻² N / C

c) for the calculation of the magnetic field we use that the field is in phase

E / B = c

B = E / c

B = 10⁻² / 3 10⁸

B = 3 10⁻¹¹ T

d) Let's use a direct proportions rule if we fear 2.5 10¹⁸ photons in an area A = 4π R² where R = 100 m how many photons are there in the area of the detector r = 1 cm, A’= 10⁻⁴ m²

#_photons = 2.5 10¹⁸ A_detector / A_sphere

#_photons = 2.5 1018 10-4 / 4π 10⁴

#_photons = 2 10⁹ photons in the detector area

for the number of photons to decrease to 1, the radius of the sphere must be 2 10⁹ m

6 0

2 years ago

Newtons _ law of motion states that every action has an equal and opposite reaction​

Newtons _ law of motion states that every action has an equal and opposite reaction