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AnnyKZ [126]
3 years ago
14

A heart defibrillator is used to enable the heart to start beating if it has stopped. This is done by passing a large current of

12 A through the body at 25 V for a very short time, usually about 3.0 ms. (a) What power does the defibrillator deliver to the body, and (b) how much energy is transferred
Physics
1 answer:
Inessa [10]3 years ago
4 0

Answer:

(a) 300 W

(b)0.90 J

Explanation:

(a) The electric power for any circuit element is given as

P=IV

Here I is current passing in the circuit and V is the voltage.

Given I = 12 A and V =25 V.

Substitute the given values, we get

P=12 A \times25 V

P = 300 W.

Thus, the power defibrillator deliver to the body is 300 W.

(b) To calculate the electric energy use the relation between electric energy, power and time as

E=Pt

Given t = 3 ms.

Substitute the values, we get

E=300 W\times 3\times 10^-^3s

E = 0.90 J.

Thus, the energy transferred is 0.90 J.

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A modern compact fluorescent lamp contains 1.4 mg of mercury (Hg). If each mercury atom in the lamp were to emit a single photon
Reika [66]

Answer:

A. 1.64 J

Explanation:

First of all, we need to find how many moles correspond to 1.4 mg of mercury. We have:

n=\frac{m}{M_m}

where

n is the number of moles

m = 1.4 mg = 0.0014 g is the mass of mercury

Mm = 200.6 g/mol is the molar mass of mercury

Substituting, we find

n=\frac{0.0014 g}{200.6 g/mol}=7.0\cdot 10^{-6} mol

Now we have to find the number of atoms contained in this sample of mercury, which is given by:

N=n N_A

where

n is the number of moles

N_A=6.022\cdot 10^{23} mol^{-1} is the Avogadro number

Substituting,

N=(7.0\cdot 10^{-6} mol)(6.022\cdot 10^{23} mol^{-1})=4.22\cdot 10^{18} atoms

The energy emitted by each atom (the energy of one photon) is

E_1 = \frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda=508 nm=5.08\cdot 10^{-7}nm is the wavelength

Substituting,

E_1 = \frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{5.08\cdot 10^{-7} m}=3.92\cdot 10^{-19} J

And so, the total energy emitted by the sample is

E=nE_1 = (4.22\cdot 10^{18} )(3.92\cdot 10^{-19}J)=1.64 J

4 0
3 years ago
An object is lifted from the surface of aspherical planet to an altitude equal to the radius of the planet.As a result, what hap
serg [7]

An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet.  

As a result, the object's <em>mass remains the same</em>, and its <em>weight decreases</em> to 1/4 of whatever it is when the object is on the planet's surface.

8 0
3 years ago
A stationary boat in the ocean is experiencing waves from a storm. The waves move at 59 km/h and have a wavelength of 145 m . Th
krek1111 [17]

Answer:

The time elapses until the boat is first at the trough of a wave is 4.46 seconds.

Explanation:

Speed of the wave, v = 59 km/h = 16.38 m/s

Wavelength of the wave, \lambda=145\ m

If f is the frequency of the wave. The frequency of a wave is given by :

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{16.38\ m/s}{145\ m}\\\\f=0.112\ Hz

The time period of the wave is given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.112\ Hz}\\\\T=8.92\ s

We need to find the time elapses until the boat is first at the trough of a wave. So, the time will be half of the time period of the wave.

T=\dfrac{8.92}{2}\\\\T=4.46\ s

Hence, this is the required solution.

5 0
3 years ago
A mass m is attached to a string connected to a force sensor on a rotating platform. The platform’s angular velocity, ω, can be
makkiz [27]

Answer:

The mass m is 0.332 kg or 332 gm

Explanation:

Given

The platform is rotating with angular speed , \omega =8.5\, \frac{rad}{sec}

Mass m is moving on platform in a circle with radius , r=0.20\, m

Force sensor reading to which spring is attached , F=4.8\, N

Now for the mass m to move in circle the required centripetal force is given by F=m\omega ^{2}r

=>4.8=m\times 8.5 ^{2}\times 0.20

=>m=0.332\, kg

Thus the mass m is 0.332 kg or 332 gm

7 0
3 years ago
Which are characteristics of the image formed by an
Over [174]

Answer:

The image is real.

The image is inverted.

The image is bigger than the object.

Explanation:

I really don't know why... I got this question wrong and they said this was the answer. I wish I did. Sorry.

8 0
3 years ago
Read 2 more answers
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