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AnnyKZ [126]
3 years ago
14

A heart defibrillator is used to enable the heart to start beating if it has stopped. This is done by passing a large current of

12 A through the body at 25 V for a very short time, usually about 3.0 ms. (a) What power does the defibrillator deliver to the body, and (b) how much energy is transferred
Physics
1 answer:
Inessa [10]3 years ago
4 0

Answer:

(a) 300 W

(b)0.90 J

Explanation:

(a) The electric power for any circuit element is given as

P=IV

Here I is current passing in the circuit and V is the voltage.

Given I = 12 A and V =25 V.

Substitute the given values, we get

P=12 A \times25 V

P = 300 W.

Thus, the power defibrillator deliver to the body is 300 W.

(b) To calculate the electric energy use the relation between electric energy, power and time as

E=Pt

Given t = 3 ms.

Substitute the values, we get

E=300 W\times 3\times 10^-^3s

E = 0.90 J.

Thus, the energy transferred is 0.90 J.

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The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

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In this problem,

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The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

sin \theta=\frac{(n+\frac{1}{2}) \lambda}{d}

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

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y=D tan \theta = (0.75 m)tan 6.17^{\circ}=0.081 m = 8.1 cm

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