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3 years ago

Solve for X. Then, Solve for Y.

Mathematics

1 answer:

ELEN [110]3 years ago

4 0

Step-by-step explanation:

Refer to attachment.

Hope it helps :D

First solved for x, then for y $.$

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Write an equation of the line that passes through (2,-4) and (0,4)

LenKa [72]

Answer:

step 1. y - y1 = m(x - x1). this is the equation given a point and a slope.

step 2. find the slope m. m = (y2 - y1)/(x2 - x1) = (4 - (-4))/(0 - 2) = 8/-2 = -4.

step 3. y - (-4) = -4(x - 2) ; y + 4 = -4x + 8.

step 4. y = -4x + 4.

7 0

2 years ago

Describe the sampling distribution of Phat. Assume the size of the Population is 25,000. N = 500 P = 0.4 Determine the Mean of t

PIT_PIT [208]

Answer:

0.022

Step-by-step explanation:

Given that :

Population size = 25000

n = 500 ; p = 0.4

Size of random sample (n) = 500

5% of population size : 0.05 * 25000 = 1250

Distribution is normally distributed since n < 5% of population size

Hence, the mean of the distribution = p = 0.4

Standard deviation = √((pq) /n)

q = 1 - p ; q = 1 - 0. 4 = 0.6

Standard deviation = √((0.4 * 0.6) /500)

Standard deviation = 0.0219089

= 0.022

5 0

3 years ago

What is the area of a circle with a radius of 42 in use 3.14 for pi

Vanyuwa [196]

The right answer is 5538.96 units^2

please see the attached picture for full solution 

Hope it helps

Good luck on your assignment

6 0

2 years ago

Read 2 more answers

Find the slope of the line through the points (-5, 2) and (5,0).

Andru [333]

Use m=y2-y1/x2-x1 when you find the slope of two coordinates :)

4 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD=√2 cm.

Zielflug [23.3K]

Given that triangle ABC is right angle triangle. CD is altitude such that AD=BC

ABC is a right angle triangle so apply Pythogorean theorem

$AC^{2} + BC^{2} = AB^{2}$

$AC^{2} + AD^{2} = AB^{2}$ (Given that AD = BC)

$AC^{2} + AD^{2} = 3^{2}$ (Given that AB=3)

$AC^{2} + AD^{2} = 9$ ...(i)

ADC is a right angle triangle so apply Pythogorean theorem

$AD^{2} + CD^{2} = AC^{2}$

$AD^{2}+(\sqrt{2})^2= AC^{2}$

$AD^{2}+2= AC^{2}$

$AD^{2}=AC^{2} -2$ ...(ii)

Plug value (ii) into (i)

$AC^{2} + AC^{2}-2 = 9$

$2AC^{2} -2=9$

$2AC^{2} =11$

$AC^{2} =\frac{11}{2}$

$AC=\sqrt{\frac{11}{2} }$

Hence final answer is $AC=\sqrt{\frac{11}{2} }$

8 0

2 years ago

Read 2 more answers