Answer:
ocean waves are converted to electricity with wave energy converter, or WEC, devices. ... The surface portion moves faster than the submerged part, and the WEC converts that relative motion into electricity
<u>Answer:</u>
<em>The percentage error in the measurement is 2.4%
</em>
<u>Explanation:</u>
The measurement made by the student is
.
But the actual value of density is
The formula to calculate percentage error is
percentage error = 
Hence percentage error in this case is given by
<em>Percentage error =
</em>
<em>=
</em>
A physical quantities value will be determines by various quantities. If errors are made in measuring any of these quantities there will be error in the measurement of the final physical quantity as well.
Here density of a substance is a derived quantity determined by measuring mass and volume of that substance.<em> If errors are made in mass and volume measurements the density value will also be erroneous.
</em>
Percent error is [(abs(experimental - actual))/(actual)] * 100
(38.0 - 40.0 ) / 40.0 = 2.0 / 40 = 0.05
0.05 * 100 = 5
since there are 2 sigfigs, the answer is 5.0 %
I made the 2 positive since the absolute value of 38.0 - 40.0 was taken
There are only 2 sigfigs because of the subtraction of 38.0 - 40.0 gives 2.0, only 2 sigfigs
Answer:
1. grasslands
Explanation: hope this helps :)
Answer:
The volume of the gas at a pressure of 65.0 kPa would be 363 mL
Explanation:
Boyle's Law is a gas law that relates the pressure and volume of a certain amount of gas, without temperature variation, that is, at constant temperature.
Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. In other words, the product P · V remains constant at the same temperature:
P*V=k
Being P1 and V1 the pressure and volume in state 1 and P2 and V2 the pressure and volume in state 2 are fulfilled:
P1*V1=P2*V2
In this case:
- P1= 45 kPa= 45,000 Pa (being 1 kPa=1,000 Pa)
- V1= 525 mL= 0.525 L (being 1 L=1,000 mL)
- P2= 65 kPa= 65,000 Pa
- V2= ?
Replacing:
45,000 Pa* 0.525 L= 65,000 Pa*V2
Solving:

V2=0.363 L=363 mL
<u><em>The volume of the gas at a pressure of 65.0 kPa would be 363 mL</em></u>