Question

A 5.0-C charge is 10m from a -2.0-C charge. The electrostatic force on the positive charge is

Answer 1

Answer:

The electrostatic force away from the negative charge is $9\times10^{8}\ N$

(b) is correct option.

Explanation:

Given that,

First charge = 5.0 C

Second charge = -2.0 C

Distance = 10 m

We need to calculate the electrostatic force on the positive charge

Using formula of electrostatic force

$F=\dfrac{kq_{1}q_{2}}{r^2}$

Where, q₁ = first charge

q₂= second charge

r = distance

Put the value into the formula

$F_{12}=\dfrac{9\times10^{9}\times5.0\times(-2.0)}{10^2}$

$F_{12}=−900000000\ N$

$F_{12}=-9\times10^{8}\ N$

The electrostatic force away from the negative charge.

Hence, The electrostatic force away from the negative charge is $9\times10^{8}\ N$

Answer 2

Answer:

9.0 × 108 N toward the negative charge

Explanation: