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zmey [24]
3 years ago
12

An offshore rig begins to spill oil in a circular patch centered on the rig. If the radius ofthe oil spill increases at a rate o

f 30 m/hr, how fast is the area of the oil spill increasing when the radiusis 100 meters

Physics
2 answers:
Tresset [83]3 years ago
7 0

Answer:

Explanation:

The area of a circle is given b

A=πr²

Then,

dA/dr= 2πr

Also give that,

dr/dt=30m/hr, r=100m

We want to find dA/dt

dA/dt=dA/dr×dr/dt

dA/dt= 2πr × 30

dA/dt= 2 ×π ×100×30

dA/dt=18849.56m²/s.

The rate of the area is 18849.56m²/s

Brut [27]3 years ago
3 0

Explanation:

Below is an attachment containing the solution.

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A force of 825 N is needed to push a car across a parking lot. Two students push a car 35 m. How much total work is done?
MaRussiya [10]
<h2>Answer :</h2><h2 />

Work is the amount of energy transferred. As per the formula

Work = Force x Distance [moved toward the direction of the force]

So as per the formula

<u>Solution : </u>

Force = 825 N

Distance = 35 m

Work = 825 (n) x 35 (m)

Work = 28875 Joules

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6 0
3 years ago
Find the currents flowing in the circuit in the figure below. (Assume the resistances are
Nitella [24]

By Kirchoff's law in left side loop

E_1 + E_2 = {r_1 + R_1 + R_4)I_1 + (R_2 + r_2) I_3

similarly kirchoff's law in right side loop

E_3 - E_4 - E_2 = (r_3 + r_4 + R_3)I_2 - (R_2 + r_2)I_3

also by junction law we know that

I_1 = I_2 + I_3

now by plug in all values we have

18 + 3 = (0.5 + 8 + 15)I_1 + (10 + 0.25)I_3

21 = 23.5I_1 + 10.25I_3

12 - 24 - 3 = (0.75 + 0.25 + 12)I_2 - (10+ 0.25)I_3

-15 = 13I_2 - 10.25I_3

So by solving above equations we have

I_1 = 0.492 A

I_2 = -0.428 A

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6 0
4 years ago
The diameter of a 12-gauge copper wire is 0.081 in. The maximum safe current it can 17) carry (in order to prevent fire danger i
Soloha48 [4]

Answer:

0.44m/s

Explanation:

drift velocity=I/nAq

diameter 12 gauge

wire=0.081inches=0.081*2.5=0.2025cm radius=0.10125cm area=pi*R^2 =20/8.5*10^22*3.14*0.10125^2*10^-4*1.6*10^-19*

V = 0.44m/s

6 0
4 years ago
An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45° relative to edge of the sidewalk. If it has
Marat540 [252]

Answer:14 s

Explanation:

Given

Velocity of ant is 0.1 m/s in a direction 45^{\circ}

if it has traveled 1 m perpendicular to the edge of the sidewalk

i.e. from diagram

\sin 45=\frac{1}{L}

L=\sqrt{2}

time=\frac{Distance}{speed}

t=\frac{\sqrt{2}}{0.1}

t=14.14 s

3 0
3 years ago
Name the type of joint present in skull.​
Artist 52 [7]

Answer:

Sutures are nonmoving joints that connect bones of the skull

Explanation:

These joints have serrated edges that lock together with fibers of connective tissue.

5 0
3 years ago
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