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puteri [66]
3 years ago
14

Suppose the tourist in question #1 instead threw the rock with an initial velocity of 8.0

Physics
1 answer:
Harman [31]3 years ago
8 0

Answer:

Explanation:u=8m/s, a=8m/s*s, t=4s

Using v= u + at

v=8+-8*4

v=-24m/s

Displacement=s

Using s=½(u+v)t

s=½(8-24)4

s=½*-16*4

s=-8*4

s=32m( you can solve without observing the negative sign)

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Reflected waves change their wavelength by ______ when reflected.
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Answer:

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Explanation:

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A 3.00 kg cart on a frictionless track is pulled by a string so that it accelerates at 2.00 m/s/s. what is the tension in the st
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5 0
3 years ago
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[TRUE/FALSE] If an object is moving at constant velocity it must be in equilibrium.
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Answer:

yes

Explanation:

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3 years ago
A ball is thrown vertically downwards with a speed 7.3 m/s from the top of a 51 m tall building. With what speed will it hit the
ddd [48]

Answer:

32.46m/s

Explanation:

Hello,

To solve this exercise we must be clear that the ball moves with constant acceleration with the value of gravity = 9.81m / S ^ 2

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are the follow

\frac {Vf^{2}-Vo^2}{2.a} =X

Where

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A = g=acceleration =9.81m/s^2

X = displacement =51m}

solving for Vf

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the speed with the ball hits the ground is 32.46m/s

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