Answer:
9.8 meters per square second
Explanation:
Free Falling Object. the value of g is 9.8 meters per square second on the surface of the earth. The gravitational acceleration g decreases with the square of the distance from the center of the earth. But for many practical problems, we can assume this factor to be a constant.
The center of mass isn't affected by the explosion.
To find the answer, we need to know about the trajectory of motion at zero external force.
<h3>How is the trajectory of an object changed when the net external force on it is zero?</h3>
- When there's no net external force acting on an object, its momentum doesn't change with time.
- As its momentum doesn't change, so it continues with the original trajectory.
<h3>Why doesn't the trajectory of firework change when it's exploded?</h3>
- When a firework is exploded, its internal forces are changed, but there's no external force.
- So, although the fragments follow different trajectories, but the trajectory of center of mass remains unchanged.
Thus, we can conclude that the center of mass isn't affected by the explosion.
Learn more about the trajectory of exploded firework here:
brainly.com/question/17151547
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Answer:4.93 m/s
Explanation:
Given
height to reach is (h )1.24 m
here Let initial velocity is u
using equation of motion
here Final Velocity v=0
a=acceleration due to gravity
u=4.93 m/s
If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula
Where | A | is the magnitude of the vector and 
is the angle that it forms with the x axis in the opposite direction to the hands of the clock.
In this problem we know the value of Ax and Ay and we need the angle .
Vector A is in the 4th quadrant
So:
So:
So:
= -47.28 ° +360° = 313 °
= 313 °
Option 4.
