Answer:
Copying materials from a source text, supplying proper documentation, but leaving out quotation marks
Explanation:
Plagiarism is when you take somebody's ideas and write them off as your own without giving them credit.
Answer:
The angle between the emergent blue and red light is 
Explanation:
We have according to Snell's law

Since medium from which light enter's is air thus 
Thus for blue incident light we have

Similarly using the same procedure for red light we have

Thus the absolute value of angle between the refracted blue and red light is

Answer:
= 591.45 T/s
Explanation:
i = induced current in the loop = 0.367 A
R = Resistance of the loop = 117 Ω
E = Induced voltage
Induced voltage is given as
E = i R
E = (0.367) (117)
E = 42.939 volts
= rate of change of magnetic field
A = area of loop = 7.26 x 10⁻² m²
Induced emf is given as


= 591.45 T/s
Answer:
The acceleration of the electron is 1.457 x 10¹⁵ m/s².
Explanation:
Given;
initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s
distance traveled by the electron, d = 0.01 m
final velocity of the electron, v = 5.4 x 10⁶ m/s
The acceleration of the electron is calculated as;
v² = u² + 2ad
(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a
(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²
(2 x 0.01)a = 2.91375 x 10¹³

Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².
Electromagnetic radiation consists of discrete packets of kinetic energy called Photons, which are characterized by a certain wavelength and energy level.
<h3>What are
photons? </h3>
The representation by a particle of a quantum of light or any other electromagnetic radiation is called photons. The energy is proportional to the frequency of radiation however it has zero mass. It travels at a constant speed. It is a carrier of energy. When the sun changes the particles into both light and heat, it is a photon. They don’t carry any electrical charge. They are like electric fields traveling through space as shown by Maxwell in his theory. They can be easily created and destroyed. They are also called light quantum.
To learn more about photons, visit:
brainly.com/question/20912241
#SPJ4