If a wave is traveling at 200 m/s and its wavelength is 0.5 meters, what is the frequency of the

Physics

1 answer:

anyanavicka [17]3 years ago

7 0

The frequency of the wave = 400/s

<h3>Further explanation</h3>

Given

v=200 m/s

λ=0.5 m

Required

The frequency of the wave

Solution

Frequency (f): number of waves in one second

The frequency is inversely proportional to the wavelength

$\tt f=\dfrac{v}{\lambda}\\\\f=\dfrac{200~m/s}{0.5~m}\\\\f=400/s$

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A) Charge q1 = +5.60 nC is on the x-axis at x = 0 and an unknown charge q2 is on the x-axis at x = -4.00 cm. The total electric

jeka94

Answer:

a) F₃₁ = 63.0 μN

b) F₃₂ = - 14.0 μN

c) q₂ = - 5.0 nC

Explanation:

Assuming that the three charges can be taken as point charges, the forces between them must obey Coulomb's Law, and can be found independent each other, applying the superposition principle.
So, we can find the force that q₁ exerts along the x-axis on q₃, as follows:

$F_{31} =\frac{k*q_{1}*q_{3} }{r_{13}^{2}} = \frac{9e9Nm2/C2*5.6e-9C*2.0e-9C}{(0.04m)^{2}} = 63.0 \mu N (1)$

Since total force exerted by q₁ and q₂ on q₃ is 49.0 μN, we can find the force exerted only by q₂ (which is along the x-axis only too) just by difference, as follows:

$F_{32} = F_{3} - F_{31} = 49.0\mu N - 63.0\mu N = -14.0 \mu N (2)$