Step-by-step explanation:
Refer to attachment.
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>
Marcos has 6 nickels and 9 quarters
<em><u>Solution:</u></em>
Let "n" be the number of nickels
Let "q" be the number of quarters
<em><u>Marcos had 15 coins in nickels and quarters</u></em>
Therefore, we can say,
number of nickels + number of quarters = 15
n + q = 15 -------- eqn 1
<em><u>He has three more quarters than nickels</u></em>
Number of quarters = 3 + number of nickels
q = 3 + n -------- eqn 2
Eqn 1 and eqn 2 represents the system of equations
<em><u>Substitute eqn 2 in eqn 1</u></em>
n + 3 + n = 15
2n + 3 = 15
2n = 15 - 3
2n = 12
<h3>n = 6</h3>
<em><u>Substitute n = 6 in eqn 2</u></em>
q = 3 + 6
<h3>q = 9</h3>
Thus Marcos has 6 nickels and 9 quarters
Answer:
2/3*22/7*r^3=231.6
2/3*22/7=2.0952
2.0952*r^3=231.6
r^3=231.6/2.0952
r^3=
Step-by-step explanation:
2/3*22/7*r^3=231.6
2.0952r^3=231.6
r^3=110.5384
cuberoot 110.5384
=4.7992
Answer:
cucumber bread and a pickle sandwich
Step-by-step explanation:
Answer:
Hence prove.
Step-by-step explanation:
Given:
∠A + ∠D = 90°
We are prove to that
Solution:
See required figure in attached file.
We know sum of the all angles of a triangle is 180°.
So, in triangle AED.
∠A + ∠E + ∠D = 180°
∠E + (∠A + ∠D) = 180°
Now, we substitute ∠A + ∠D = 90° in above equation.
∠E + 90° = 180°
∠E = 180° - 90°
∠E = 90°
Using Pythagoras Theorem for triangle ADE and triangle BEC.
Now, we add both above equations.
--------(1)
Similarly, Using Pythagoras Theorem for triangle AEC and triangle BED.
Now, we add both above equations.
--------(2)
We get From equation 1 and equation 2.
Hence prove,
