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MAVERICK [17]
3 years ago
6

onsider the following reaction at equilibrium: CO(g) + Cl2(g)=======COCl2(g) Predict whether the reaction will shift left,shift

right, or remain the unchanged upon each of the following disturbances.a) COCl2 is added to thereaction mixtureb) Cl2 is added to thereaction mixturec) COCl2 is removed fromthe reaction mixture
Chemistry
1 answer:
velikii [3]3 years ago
6 0

Explanation:

CO(g) + Cl2(g) ⇄ COCl2(g)

This question is based on Le Chatelier's principle.

Le Chatelier's principle is an observation about chemical equilibria of reactions. It states that changes in the temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system in order to achieve a new equilibrium state.

a) COCl2 is added to the reaction mixture

COCL2 is a product in the reaction. If we add additional product to a system, the equilibrium will shift to the left, in order to produce more reactants. The reaction would shift to the left.

b) Cl2 is added to the reaction mixture

if we add reactants to the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

c) COCl2 is removed from the reaction mixture

if we remove products from the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

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slavikrds [6]

Answer:

Carbon moves from living things to the atmosphere. Each time you exhale, you are releasing carbon dioxide gas (CO2) into the atmosphere. Animals and plants need to get rid of carbon dioxide gas through a process called respiration. Carbon moves from fossil fuels to the atmosphere when fuels are burned.

4 0
3 years ago
The energy needed to remove an electron is called ionization energy.
salantis [7]
<h2>                             Emma here<em>!</em></h2>

Answer:

im pretty sure its decreases going across a row (left to right)

Explanation:

As you move from left to right across a period on the periodic table the size of an atom will decrease

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7 0
3 years ago
1.Calculate the molarity of a 6.15% (w/v%) sodium hypochlorite (NaOCl) solution (i.e. in a 100 ml of solution there is 6.15 gram
shtirl [24]

Answer:

C  U  M

Explanation:

3 0
3 years ago
Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe
Illusion [34]

Answer:

a. Kp=1.4

P_{A}=0.2215 atm

P_{B}=0.556 atm

b.Kp=2.0 * 10^-4

P_{A}=0.495atm

P_{B}=0.00995 atm

c.Kp=2.0 * 10^5

P_{A}=5*10^{-6}atm

P_{B}=0.9999 atm

Explanation:

For the reaction  

A(g)⇌2B(g)

Kp is defined as:

Kp=\frac{(P_{B})^{2}}{P_{A}}

The conditions in the system are:

          A                    B

initial   0                1 atm

equilibrium x       1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.    

Replacing these values in the expression for Kp we get:

Kp=\frac{(1-2x)^{2}}{x}

Working with this equation:

x*Kp=(1-2x)^{2} - -> x*Kp=4x^{2}-4x+1- - >4x^{2}-(4+Kp)*x+1=0

This last expression is quadratic expression with a=4, b=-(4+Kp) and c=1

The general expression to solve these kinds of equations is:

x=\frac{-b(+-)*\sqrt{(b^{2}-4ac)}}{2a} (equation 1)

We just take the positive values from the solution since negative partial pressures don´t make physical sense.

Kp = 1.4

x_{1}=\frac{(1.4+4)+\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=1.128

x_{1}=\frac{(1.4+4)-\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=0.2215

With x1 we get a partial pressure of:

P_{A}=1.128 atm

P_{B}=1-2*1.128 = -1.256 atm

Since negative partial pressure don´t make physical sense x1 is not the solution for the system.

With x2 we get:

P_{A}=0.2215 atm

P_{B}=1-2*0.2215 = 0.556 atm

These partial pressures make sense so x2 is the solution for the equation.

We follow the same analysis for the other values of Kp.

Kp=2*10^-4

X1=0.505

X2=0.495

With x1

P_{A}=0.505atm

P_{B}=1-2*0.505 = -0.01005 atm

Not sense.

With x2

P_{A}=0.495atm

P_{B}=1-2*0.495 = 0.00995 atm

X2 is the solution for this equation.  

Kp=2*10^5

X1=50001

X2=5*10^{-6}

With x1

P_{A}=50001atm

P_{B}=1-2*50001=-100001atm

Not sense.

With x2

P_{A}= 5*10^{-6}atm

P_{B}=1-2*5*10^{-6}= 0.9999 atm

X2 is the solution for this equation.  

8 0
4 years ago
How many sub-energy levels does the 2nd MEL have?
DedPeter [7]

Answer:

n=  | Shell            |       Maximum Number of Electrons

1    | 1st Shell      |      2

2   | 2nd Shell      |      8

3   | 3rd Shell        |      18

4   |  4th Shell        |      32

Explanation: cause :)

5 0
3 years ago
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