Answer:
Hi there!
Your answer is:
2 & 1/4 <u>OR</u> 2.25 cups fills the container!
Step-by-step explanation:
If 1 & 1/2 (aka 3/2) fills 2/3 of the container, then:
we know that <em>half</em> of 3/2s fills 1/3 of the container
To find half of 3/2, we multiply 3/2 by the <em><u>inverse</u></em> of 2, which is 1/2.
3/2÷2
3/2×1/2 = 3/4 ths
Now that we know 3/4ths fills 1/3 of the container, we add that to 1& 1/2.
3/4+ 1&1/2 = 2 & 1/4
Check your work!
3/4 × 3 should equal 2&1/4 if we are correct
3/4 × 3/1 = 9/4.
Simplify!
9/4 = 2&1/4
That tells us that <u>we</u><u> </u><u>are</u><u> </u><u>correct</u><u>!</u>
Hope this helps!
Answer:
5.92
Step-by-step explanation:
16*37=
592
put the decimals in next
Answer: x = 22
Step-by-step explanation: Since x is unknown, we want to isolate it and determine what it equals. We know that x - 3 gives us 19, but we don't want to know what x - 3 is, just x. So we can add three to both sides of the equation, to get our answer and keep it balanced. As a result, we get x = 22
First using the given two points we can find the slope (m) of the line

Thus the slope of given line is 1.
Using slope and a point (0,1) we can write the equation in point slope form as
y - 1= 1(x-0)
y - 1 = x
The above equation is the point-slope form of the equation.
![\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) \\\\ a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 729=27^2\\ \qquad (3^3)^2\\ 1000=10^3 \end{cases}\implies 729^{15}+1000\implies ((3^3)^2)^{15}+10^3 \\\\\\ ((3^2)^{15})^3+10^3\implies (3^{30})^3+10^3\implies (3^{30}+10)~~[(3^{30})^2-(3^{30})(10)+10^2] \\\\\\ (3^{30})^3+10^3\implies (3^{30}+10)~~~~[(3^{60})-(3^{30})(10)+10^2]](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdifference%20and%20sum%20of%20cubes%7D%20%5C%5C%5C%5C%20a%5E3%2Bb%5E3%20%3D%20%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29%20%5C%5C%5C%5C%20a%5E3-b%5E3%20%3D%20%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20729%3D27%5E2%5C%5C%20%5Cqquad%20%283%5E3%29%5E2%5C%5C%201000%3D10%5E3%20%5Cend%7Bcases%7D%5Cimplies%20729%5E%7B15%7D%2B1000%5Cimplies%20%28%283%5E3%29%5E2%29%5E%7B15%7D%2B10%5E3%20%5C%5C%5C%5C%5C%5C%20%28%283%5E2%29%5E%7B15%7D%29%5E3%2B10%5E3%5Cimplies%20%283%5E%7B30%7D%29%5E3%2B10%5E3%5Cimplies%20%283%5E%7B30%7D%2B10%29~~%5B%283%5E%7B30%7D%29%5E2-%283%5E%7B30%7D%29%2810%29%2B10%5E2%5D%20%5C%5C%5C%5C%5C%5C%20%283%5E%7B30%7D%29%5E3%2B10%5E3%5Cimplies%20%283%5E%7B30%7D%2B10%29~~~~%5B%283%5E%7B60%7D%29-%283%5E%7B30%7D%29%2810%29%2B10%5E2%5D)
now, we could expand them, but there's no need, since it's just factoring.