95 POINTS FOR AWNSER

Mathematics

2 answers:

kari74 [83]2 years ago

7 0

Answer:

$yes \: he \: is \: correct \\ \underline{\boxed{(\triangle{ \delta}) = 8}}$

Step-by-step explanation:

$change \: in \: temp. \: ( \triangle{ \delta}) = t_2 - t_1 \\ hence \to \\( \triangle{ \delta}) = (- 2) - (- 10) \\ (\triangle{ \delta}) = - 2 + 10 \\ (\triangle{ \delta}) = 10 - 2 \\ (\triangle{ \delta}) = 8$

kap26 [50]2 years ago

6 0

Answer:

Step-by-step explanation:

Luke only does it mathematically, he didnt bothet to check first by following step by step explanation

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If Casey deposits $16 into his lunch account each week, how much will be deposited in 5 weeks? If Casey decides to buy lunch for

Ivanshal [37]

Answer:

The exact number would be 26.66666667 but it would be 26.

Step-by-step explanation:

Usually when dealing with decimals anything 5 and up would be rounded up but since we are dealing with money we don't round up. Since his friends lunch cost $3 every lunch the most he will be able to buy is 26. He will have about $2.5 left over which he cannot buy a lunch with so thats why you dont round up.

8 0

3 years ago

A computer program contains one error. In order to find the error, we split the program into 6 blocks and test two of them, sele

Aleksandr-060686 [28]

There are $\dbinom62$ ways of selecting two of the six blocks at random. The probability that one of them contains an error is

$\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13$

So $X$ has probability mass function

$f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}$

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.

The expected value of finding an error is then

$\displaystyle\sum_{x=0}^1xf_X(x)=0\times\dfrac23+1\times\dfrac13=\dfrac13$