If 14 grams of hydrogen reacted with 24.7 grams of oxygen 27.7875 grams of water will be formed.
Explanation:
2H2+O2----------->2H2O.
- From the above equation, we can say that 4g of Hydrogen will react with 32 g of oxygen.
- In this question, Hydrogen is in excess amount.
- 32 g of Oxygen will react with = 4 g of H2.
- Therefore 24.7g of Oxygen will react with =24.7x4/32= 3.0875 g H2.
- The remaining 10.9125g of H2 will be left unreacted.
- Therefore the amount of water formed=(24.7+3.0875)=27.7875 g
When the solubility is the amount of solute that dissolved in a unit volume of the solvent.
and when the balanced reaction equation is:
so, by using the ICE table:
Cd(OH)2(s) ↔ Cd2+ + 2OH-
initial 0 0
change +X +2X
Equ X 2X
so the Ksp expression = [Cd2+] [OH-]^2
and we have Ksp = 7.2 x 10^-15
and when we assume the solubility = X
by substitution:
7.2 x 10^-15 = (X) (2X)^2
7.2 x 10^-15 = X*4X^2
7.2 x 10^-15 = 4X^3
∴X = ∛(7.2x10^-15)/4
= 1.22 x 10^-5 M
∴ the solubility = X = 1.22 x 10^-5 M
Standard entropy of the compounds of interest are as follows,
= 212.1 J/K.mol
= 205.0 J/K.mol
= 213.6 J/K.mol
= 69.9 J/K.mol
Now for the reaction:
C6H12O6(s) + 6O2(g) —->6CO2(g) + 6H2O(l)
ΔS°reaction = ∑
- ∑
∴ ΔS°reaction =( 6
+ 6
) - (
+ 6
= 205.0 J/K.mol)
∴ ΔS°reaction = [6 (213.6) + 6 (69.9 )] - [(212.1) + 6(205.0)]
∴ ΔS°reaction = 258.9
Answer:
A substance that protects cells from the damage caused by free radicals (unstable molecules made by the process of oxidation during normal metabolism). Free radicals may play a part in cancer, heart disease, stroke, and other diseases of aging.