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Rina8888 [55]
3 years ago
10

In isosceles triangle △ABC,

Mathematics
1 answer:
belka [17]3 years ago
4 0

Angle values in fraction form

  • A = 220/3
  • B = 100/3
  • C = 200/3

Angle values in decimal form

  • A = 73.333
  • B = 33.333
  • C = 73.333

For each decimal value, the '3's go on forever.

=============================================

Work Shown:

Check out the diagram below. Since AD bisects angle BAC, this means the two smaller pieces (angle DAB and angle DAC) are equal to one another. Let's call those smaller pieces x for now. They combine to 2x which is the measure of angle BAC.

Angle BCA is 2x since this is the other base angle, and the two base angles are congruent.

Let y be the measure of angle ADC. It's supplementary to the 110 degree angle.

y+110 = 180

y = 180-110

y = 70

Now focus on triangle ACD. All three angles of a triangle add to 180

A+D+C = 180

x+y+2x = 180

3x+y = 180

3x+70 = 180

3x = 180-70

3x = 110

x = 110/3

This means each base angle is

2x = 2*(110/3) = 220/3

So we know that A = 220/3 and C = 220/3 are the two base angles of triangle ABC.

The last step is to find the vertex angle B

A+B+C = 180

220/3 + B + 220/3 = 180

B+440/3 = 180

B = 180 - 440/3

B = 180*(3/3) - 440/3

B = 540/3 - 440/3

B = 100/3

------------------------------------

So in summary we have

  • A = 220/3
  • B = 100/3
  • C = 220/3

as the three angles for triangle ABC. Those are the exact fractional values.

The approximate decimal values are

  • A = 73.333
  • B = 33.333
  • C = 73.333

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Answer:

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Triangle C:

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Step-by-step explanation:

Let's find the distance of the legs for the 3 right triangles.

<u>Triangle A</u>

The smaller leg (SL) is from (2,5) to (2,8), so the length is given by the distance in the y-axis:

SL_{A} = 8 - 5 = 3

Hence, the lenght of the smaller leg is 3.

The longer leg (LL) is from (-8, 8) to (2, 8), so the length is given by the distance in the x-axis:

LL_{A} = 2 - (-8) = 10

Then, the length of the longer leg is 10.  

Now, we can find the hypotenuse (H) by using Pitagoras:

H_{A} = \sqrt{SL_{A}^{2} + LL_{A}^{2}} = \sqrt{3^{2} + 10^{2}} = 10.4

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The SL is from (3, -9) to (7, -9)

The length of the SL is:

SL_{B} = 7 - 3 = 4

The LL is from (7, -9) to (7, 4)

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The hypotenuse is:

H_{B} = \sqrt{4^{2} + 13^{2}} = 13.6

<u>Triangle C</u>

The SL is from (-10, -6) to (-10, -1)

The length of the SL is:

SL_{C} = -1 - (-6) = 5

The LL is from (-10, -6) to (-3, -6)  

The length of the LL is:

LL_{C} = -3 - (-10) = 7

The hypotenuse is:

H_{C} = \sqrt{5^{2} + 7^{2}} = 8.6

I hope it helps you!

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