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2 years ago

Hi! I have a question. If I ask a question and someone answers, do I lose my points?

Mathematics

2 answers:

castortr0y [4]2 years ago

7 0

Answer:

you use points to post questions so technically yes because only 2 answers are needed and when you use 10 points 5 points are given to each person who answers and only 2 people can answer

Step-by-step explanation:

kotegsom [21]2 years ago

4 0

Answer:

yes u will loose it

Step-by-step explanation:

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Determine if f(x, y) = 10 − x^2 − y^2

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Step-by-step explanation:

f(x,y)=10-x^2-y^2

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f(x,y)=10-x^2-y^2

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A consumer group is testing camp stoves. To test the heating capacity of a stove, they measure the time required to bring 2 quar

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Answer:

The decision rule is

Reject the null hypothesis

The conclusion is

There is sufficient evidence to show that there is a difference between the performances of these two models

The 95% confidence interval is $0.224 < \mu_1 - \mu_2 < 2.776$

Step-by-step explanation:

From the question we are told that

The sample size is n = 36

The first sample mean is $\= x_1 = 11.4$

The first standard deviation is $s_1 = 2.5$

The second sample mean is $\= x_2 = 9.9$

The second standard deviation is $s_2 = 3.0$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu_1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$z = \frac{ (\= x_1 - \= x_2 ) - (\mu_1 - \mu_2 ) }{ \sqrt{ \frac{s_1^2 }{n} + \frac{s_2^2 }{ n} } }$

=> $z = \frac{ ( 11.4 - 9.9) - 0 }{ \sqrt{ \frac{2.5^2 }{36} + \frac{ 3^2 }{36 } } }$

=> $z = 2.3$

From the z table the area under the normal curve to the left corresponding to 2.3 is

$P( Z > 2.3 ) = 0.010724$

Generally the p-value is mathematically represented as

$p-value = 2 * P( Z > 2.3 )$

=> $p-value = 2 * 0.010724$

=> $p-value = 0.02$

From the value obtained we see that $p-value < \alpha$ hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is sufficient evidence to show that there is a difference between the performances of these two models

Considering question b

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{s_1^2 }{n } + \frac{s_2^2}{n}}$

=> $E = 1.96 * \sqrt{ \frac{2.5^2 }{ 36 } + \frac{ 3^2}{36}}$

=> $E = 1.276$

Generally 95% confidence interval is mathematically represented as

$( \= x_1 - \= x_2) -E < \mu_1 - \mu_2 < ( \= x_1 - \= x_2) + E$

=> $( 11.4 - 9.9 ) -1.276 < \mu_1 - \mu_2 < ( 11.4 - 9.9 ) + 1.276$

=> $0.224 < \mu_1 - \mu_2 < 2.776$

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