Question

What is the number of millimoles of H+ in 1.653 mmol of oxalic acid dehydrate?Remember that oxalic acid is diprotic.

Answer 1

Answer: 3.306 mmol

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

Molarity

n= moles of solute  

$V_s$ = volume of solution in ml

$C_2O_4H_2.2H_2O\rightarrow C_2O_4^{2-}+2H^++2H_2O$

According to stoichiometry:

1 mole of $C_2O_4H_2$ gives 2 moles of $H^+$

1.653 mmol of $C_2O_4H_2$ gives =$\frac{2}{1}\times 1.653=3.306mmo$ of $H^+$

Thus number of millimoles of $H^+$ are 3.306