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3 years ago

Which factors are involved in earthquakes formation (multiple choice)

Physics

2 answers:

RoseWind [281]3 years ago

6 0

Answer:

1- Option (A) and (D)

2- Mercalli scale measures earthquake magnitude depending on its size

Explanation:

Earthquake occurs due to the sudden shaking of the earth. During an earthquake, seismic waves are produced, namely P wave and S wave, and this waves propagates through the interior of the earth depending upon its magnitude and intensity, thus<u> travelling below the earth's surface</u>.

Due to this wave propagation<u> the rocks breaks</u> and adjust themselves and the faulting occurs along the weak zones.

<u>According to the Mercalli scale, the earthquake is measured in terms of intensity of the shaking of the ground and the size</u>. If a small area is affected then its magnitude is less but if an earthquake affects a large area then it is a severe one.

kap26 [50]3 years ago

5 0

A.rock breaking and D movement below ground

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3 years ago

One horse is pulling a 755 kg sled straight ahead applying a force of 1988 N. If the acceleration of the sled is 1.36 m/s2, what

Inessa [10]

Answer:

The coefficient of kinetic friction is 0.13

Explanation:

Newton's second law states that the acceleration of an object is proportional to the net force on it, the factor of proportionality is the mass. So, we can express that law mathematically as:

$\sum\overrightarrow{F}=m\overrightarrow{a}$ (1)

With F the net force, m the mass and a the acceleration of the object. In our case we're interested on what's happening to the sled, then we have to analyze the forces on it, those forces are the weight and the normal force on the vertical direction and the pulling force and frictional force in the horizontal direction. So, because (1) is a vector equation we can express that in their vertical (y) and horizontal (x) components:

$F_y=ma_y$ (2)

$F_x=ma_x$ (3)

On y we have that the acceleration is zero because the sled is not moving upward or downward, remember that the net force on y is the weight (W) pointing downward and the normal force pointing upward:

$F_y=W+n=0$

Following the convention that positive is upward and negative downward, W=mg=(755)(-9.81):

$F_y=(755)(-9.81)+n=0$

$n=7406.55 N$ (4)

Now on the x direction we have the sum of the forces is the pulling force (T) and friction force (f)

$F_x=F+f=ma_x$

Choosing the direction where the horse is pulling F=1988N and the acceleration should be positive too, then:

$1988+f=m(1.36)$

$f=(755)(1.36)-1988=-961.2 N$

The negative sign means it's in the opposite direction the horse is pulling

The frictional force is related with the coefficient of kinetic friction in the next way:

$|f|=\mu_k n$

with μk the coefficient of kinetic friction, and n the normal force that we already found on (4), so we simply solve the last equation for μk:

$\mu_k=\frac{|f|}{n}=\frac{961.2}{7406.55}=0.13$

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4 years ago