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Blizzard [7]
3 years ago
15

Which factors are involved in earthquakes formation (multiple choice)

Physics
2 answers:
RoseWind [281]3 years ago
6 0

Answer:

1- Option (A) and (D)

2- Mercalli scale measures earthquake magnitude depending on its size

Explanation:

Earthquake occurs due to the sudden shaking of the earth. During an earthquake, seismic waves are produced, namely P wave and S wave, and this waves propagates through the interior of the earth depending upon its magnitude and intensity, thus<u> travelling below the earth's surface</u>.

Due to this wave propagation<u> the rocks breaks</u> and adjust themselves and the faulting occurs along the weak zones.

<u>According to the Mercalli scale, the earthquake is measured in terms of intensity of the shaking of the ground and the size</u>. If a small area is affected then its magnitude is less but if an earthquake affects a large area then it is a severe one.

kap26 [50]3 years ago
5 0
A.rock breaking and D movement below ground
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(15pts) A hungry 12.0 kg fish is coasting from west to east at 75 cm/s when it suddenly swallows a 1 kg fish swimming towards it
faust18 [17]

Answer:

The speed of the big fish after swallowing the small fish is 0.38 m/s.

Explanation:

Consider west to east direction as positive and the opposite direction as negative.

Given:

Mass of big fish (m₁) = 12.0 kg

Initial velocity of big fish (u₁) = 75 cm/s = 0.75 m/s

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Initial velocity of small fish (u₂) = -4 m/s (Direction is opposite to u₁)

After swallowing the small fish, both the fishes move together with same velocity. Let the velocity be 'v'.

So, as there are no effects of drag or any other forces, the given scenario can be considered as a case of inelastic collision where the objects move together with same velocity after collision.

The momentum is conserved in inelastic collision. Therefore,

Initial momentum of the fishes = Final momentum of the fishes

m_1u_1+m_2u_2=(m_1+m_2)v\\\\v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}

Now, plug in the given values and solve for 'v'. This gives,

v=\frac{12.0\times 0.75+1\times (-4)}{12.0+1}\\\\v=\frac{9-4}{13}\\\\v=\frac{5}{13}=0.38\ m/s

Therefore, the speed of the big fish after swallowing the small fish is 0.38 m/s

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