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IgorLugansk [536]
3 years ago
12

An observer sitting on shore sees a canoe traveling 5.0 m/s east, and a sailboat traveling 15.0 m/s west. What is the velocity o

f the sailboat as observed on the canoe (relative to the canoe)?
Physics
1 answer:
Dovator [93]3 years ago
3 0

Answer:

Vs/c = 20 [m/s]

Explanation:

This is a problem of relative velocities, as velocity is a vector we can use addition or subtraction of vectors for the solution.

We are asked for the velocity of the sailboat with respect to an observer located in the canoe.

V_{s/c}=V_{sailboat}-V_{canoe}\\V_{s/c}=15-(-5)\\V_{s/c}=20[m/s]

Why is the speed of the canoe negative?, it is negative because the canoe moves in the opposite direction to the sailboat.

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If the road becomes wet or crowded, you should ____. slow down and increase your following distance All choices are incorrect. m
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The first one.

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What environmental factors affect sound?
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Here are 5:

Distance from source to receiver

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and there are many more...

Hope that was helpful.Thank you!!!

7 0
3 years ago
In the reaction 2Ca + O2 → 2CaO for every 2 Ca you will need how much O2?
Serjik [45]

Answer:

1

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5 0
2 years ago
block with of mass m is at rest on horizontal frictionless surface at time t=0. A force given by F=Bt+C is applied horizontally
Alexeev081 [22]

Answer:

v_{2} =\frac{1}{2}

Explanation:

From the second law of Newton movement laws, we have:

F=m*a, and we know that a is the acceleration, which definition is:

a=\frac{dv}{dt}, so:

F=m*\frac{dv}{dt}\\\frac{dv}{dt}=\frac{F}{m}=\frac{\frac{1}{2}(t+1)}{4}=\frac{t+1}{8}

The next step is separate variables and integrate (the limits are at this way because at t=0 the block was at rest (v=0):

dv=\frac{1}{8}(t+1)dt\\\int\limits^{v_{2}}_0 \, dv=\int\limits^{2}_{0} {\frac{1}{8}(t+1)} \, dt

v_{2}=\frac{1}{8}*(\frac{t^{2}}{2}+t) (This is the indefinite integral), the definite one is:

v_{2}=\frac{1}{8}*(2+2)=\frac{1}{2}

3 0
3 years ago
Read the following questions and answer them using complete sentences. Be sure to fully explain your answers.
astra-53 [7]

Wave power can be regarded as a reliable source of energy because the ocean currents are always moving.

<h3>What can be the challenges of wave power?</h3>

Wave power is a device that can be used to convert the mechanical energy of the ocean waves into electrical energy based on the principle of conservation of energy.

The major challenges that face the use of wave power in electricity generation is the unreliability of the waves which leads to uncertainty in the quantity of power generated Also, the wave direction and direction of ocean currents all limit the amount of power generated by this method. However, in spite of challenges, it can be regarded as a reliable source of energy because the ocean currents are always moving.

Learn more about wave power:brainly.com/question/1362067

#SPJ1

6 0
2 years ago
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