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klemol [59]
3 years ago
11

If you heat soup on a stove, what happens to the movement of the soup’s particles?

Physics
2 answers:
Rasek [7]3 years ago
8 0
B, they move faster.
deff fn [24]3 years ago
6 0
Answer: B. The particles mover faster.
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An object is moving on a horizontal frictionless surface. if the net force applied to the object in the direction of motion is d
sukhopar [10]

Answer:

doubled

Explanation:

F=ma1----------(1)

2F = ma2-------(2)

Divide 2nd equation by 1st one

we get a1×2=a2

5 0
2 years ago
Frequencies of sound waves higher than those we can hear is called?
ludmilkaskok [199]

Answer:

utrasonic

Explanation:

these are sounds beyond our hearing capacity range of 20-20kHz

8 0
3 years ago
Read 2 more answers
U1=20 m/s turn it to km/h
notka56 [123]
It is 72 km/h
I hope it helps
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3 years ago
To prevent accidental electric shock, most electrical equipment is A. painted. B. isolated. C. coated. D. grounded.
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D. It is Grounded below ground 
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3 years ago
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An object is originally moving at a constant velocity of 8 m/s in the -x direction. It moves at this constant velocity for 3 sec
aivan3 [116]

Answer:

244.64m

Explanation:

First, we find the distance traveled with constant velocity. It's simply multiplying velocity time the time that elapsed:

x = V*t = -8\frac{m}{s} *3s = -24m

After this, the ball will start traveling with a constant acceleration motion. Due to the fact that the acceleration is the opposite direction to the initial velocity, this motion will have 2 phases:

1. The velocity will start to decrease untill it reaches 0m/s.

2. Then, the velocity will start to increase at the rate of the acceleration.

The distance that the ball travels in the first phase can be found with the following expression:

v^2 = v_0^2 + 2a*d

Where v is the final velocity (0m/s), v_0 is the initial velocity (-8m/s) and a is the acceleration (+9m/s^2). We solve for d:

d = \frac{v^2 - v_0^2}{2a} = \frac{(0m/s)^2 - (-8m/s)^2}{2*7m/s^2}= -4.57m

Now, before finding the distance traveled in the second phase, we need to find the time that took for the velocity to reach 0:

t_1 = \frac{v}{a} = \frac{8m/s}{7m/s^2} = 1.143 s

Then, the time of the second phase will be:

t_2 = 9s - t_1 = 9s - 1.143s = 7.857s

Using this, we using the equations for constant acceleration motion in order to calculate the distance traveled in the second phase:

x = \frac{1}{2}a*t^2 + v_0*t + x_0

V_0, the initial velocity of the second phase, will be 0 as previously mentioned. X_0, the initial position, will be 0, for simplicity:

x = \frac{1}{2}*7\frac{m}{s^2}*t^2 + 0m/s*t + 0m = 216.07m

So, the total distance covered by this object in meters will be the sum of all the distances we found:

x_total = 24m + 4.57m + 216.07m = 244.64m

8 0
3 years ago
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