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Papessa [141]
3 years ago
6

What comet is currently visible from some spot on earth

Physics
1 answer:
Alex787 [66]3 years ago
3 0

c/2017EP , 21 p or giaconbini-zimmer or simply "2lp" or 46p / wirtanen

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Potential difference of a battery is 2.2 V when it is connected
Alchen [17]

Answer:

1.1ohms

Explanation:

According to ohms law E = IR

If potential difference of a battery is 2.2 V when it is connected across a resistance of 5 ohm and if suddenly the voltage Falls to 1.8V then the current in the 5ohms resistor I = V/R = 1.8/5

I = 0.36A (This will be the load current).

Before we can calculate the value of the internal resistance, we need to know the voltage drop across the internal resistance.

Voltage drop = 2.2V - 1.8V = 0.4V

Then we calculate the internal resistance using ohms law.

According to the law, V = Ir

V= voltage drop

I is the load current

r = internal resistance

0.4 = 0.36r

r = 0.4/0.36

r = 1.1 ohms

6 0
3 years ago
If the measured resistance of a lamp is 45 ohms when it operates at a power of 80.0 watts, what is the current in the lamp?
melisa1 [442]
P= R.I^2 so 80=45*I^2
I=sqrt(80/45)= 1.33A
4 0
3 years ago
Which action will decrease the gravitational force between two objects?
WITCHER [35]

Answer:

It’s D

Explanation:

6 0
3 years ago
Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. Calculate the frequency of this l
12345 [234]

Answer:

5.71×10¹⁴ Hz

Explanation:

Applying,

v = λf................. Equation 1

Where v = speed of the electromagnetic radiation, λ = wavelength of the electromagnetic radiation, f = frequency

make f the subject of the equation

f = v/λ............. Equation 2

From the question,

Given: λ = 525 nm = 5.25×10⁻⁷ m,

Constant: Speed of electromagnetic wave (v) = 3.0×10⁸ m/s

Substitute these values into equation 2

f = (3.0×10⁸)/(5.25×10⁻⁷)

f = 5.71×10¹⁴ Hz

Hence the frequency of light is 5.71×10¹⁴ Hz

5 0
3 years ago
A rock weighing 98 newtons is pushed off the edge of a bridge 50 meters above the ground. What was the potential energy of the r
lidiya [134]
Ep = 4900 because Ep = wh
4 0
3 years ago
Read 2 more answers
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