Answer:
a. the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon; the force is 1.38 × 10⁸ greater than muon
Explanation:
F= ma
v²=u² -2aS
(1.56 ✕ 10⁶)²=(2.40 ✕ 10⁶)²-2a(1220)
a=1.36×10⁹m/s²
recall
F=ma
F = 1.88 ✕ 10⁻²⁸ kg × 1.36×10⁹m/s²
F= 2.55 × 10⁻¹⁹N
the magnitude of the force experienced by the muon is 2.55 × 10⁻¹⁹N
b. this force compare to the weight of the muon
F/mg= 2.55 × 10⁻¹⁹/ (1.88 ✕ 10⁻²⁸ × 9.8)
= 1.38 × 10⁸
The answer is ....... none of the above. The reactivity of an element is based on its valence electrons
Answer:
a. 
b.
Explanation:
#Apply surface charge density, electric field, and Gauss law to solve:
a. Surface charge density is defined as charge per area denoted as 
, and the strength of the electric field outside the sphere 
Using Gauss Law, total electric flux out of a closed surface is equal to the total charge enclosed divided by the permittivity.
#surface charge outside sphere.
Hence, the new charge density on the outside of the sphere is
b. The strength of the electric field just outside the sphere is calculated as:
From a above, we know the new surface charge to be ,
Hence, the strength of the electric field just outside the sphere is
Rubbing materials together Can strip electrons off atoms.
Answer:
it would be least to graetest
Explanation:
10-84
