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3 years ago

Reflection of the images example

Physics

1 answer:

NISA [10]3 years ago

8 0

Answer:

reflection of water ,sound and water waves etc

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An ice skater has a moment of inertia of 5.0 kg · m2when her arms are outstretched, and at this time she is spinning at 3.0 rev/

KatRina [158]

Answer:

Explanation:

Given

Initial Moment of Inertia $I_1=5 kg-m^2$

initial Spin $N_1=3 rev/s$

$\omega _1=2\pi N_1=2\pi 3=6\pi rad/s$

Final Moment Moment of Inertia $I_2=2 kg-m^2$

Conserving Angular momentum

$L_1=L_2$

$I_1\omega _1=I_2\omega _2$

$5\times 6\pi=2\times \omega _2$

$\omega _2=15\pi rad/s$

$N_2=\frac{\omega _2}{2\pi }$

$N_2=\frac{15\pi }{2\pi}=7.5 rev/s$

8 0

3 years ago

What is the name of the force that opposes, or the opposite of gravity ???!!

Novosadov [1.4K]

Answer:

Tension.

<em><u>tension</u></em> is the name of force that opposes or goes opposite of gravity

Hope this helps!

4 0

2 years ago

Read 2 more answers

A body travel according to the law x(t)=2t+3t3 calculate the accelaration of body at t=2s

faust18 [17]

Answer:

28m/s

Explanation:

Given law,

⇒ x(t) = 2t + 3t³

Where, t = 2s

Then,

⇒ x(2) = 2(2) + 3(2)³

⇒ 4 + 3(8)

⇒ 4 + 24

⇒ 28 m/s

Acceleration is 28m/s

4 0

3 years ago

Calculate the average distances the car and the washer traveled from the top of the track. Record the average in Table A of your

Romashka-Z-Leto [24]

The answer for both is 247 cm

7 0

2 years ago

Read 2 more answers

The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume tha

belka [17]

Given that,

Energy $H=2.7\times10^{31}\ W$

Surface temperature = 11000 K

Emissivity e =1

(a). We need to calculate the radius of the star

Using formula of energy

$H=Ae\sigma T^4$

$A=\dfrac{H}{e\sigma T^4}$

$4\pi R^2=\dfrac{H}{e\sigma T^4}$

$R^2=\dfrac{H}{e\sigma T^4\times4\pi}$

Put the value into the formula

$R=\sqrt{\dfrac{2.7\times10^{31}}{1\times5.67\times10^{-8}\times(11000)^4\times 4\pi}}$

$R=5.0\times10^{10}\ m$

(b). Given that,

Radiates energy $H=2.1\times10^{23}\ W$

Temperature T = 10000 K

We need to calculate the radius of the star

Using formula of radius

$R^2=\dfrac{H}{e\sigma T^4\times4\pi}$

Put the value into the formula

$R=\sqrt{\dfrac{2.1\times10^{23}}{1\times5.67\times10^{-8}\times(10000)^4\times4\pi}}$

$R=5.42\times10^{6}\ m$

Hence, (a). The radius of the star is $5.0\times10^{10}\ m$

(b). The radius of the star is $5.42\times10^{6}\ m$

8 0

2 years ago