<h3>
Answer:</h3>
3.5 Newton
<h3>
Explanation:</h3>
We are given;
Mass of the ball = 140 g
Acceleration = 25 m/s²
Required to find the force;
- According to Newton's second law of motion, the resultant force on a body in motion and the rate of change in linear momentum are directly proportional.
- That is;

- Thus; F = ma , where F is the resultant force, m is the mass and a is the acceleration.
To get the force we substitute the value of m and a in the formula;
Therefore;
F = 0.14 kg × 25 m/s²
= 3.5 N
Hence, the force needed to accelerate the ball is 3.5 N
The amount of oxygen that are produced when 1.06 grams of potassium chlorate decompose completely is 0.64 grams.
<h3>What is the relation between mass & moles?</h3>
Relation between the mass and moles of any substance will be represented as:
- n = W/M, where
- W = given mass
- M = molar mass
Moles of potassium chlorate = 1.66g / 122.5g/mol = 0.0135mole
Given chemical reaction is:
2KClO₃ → 2KCl + 3O₂
From the stoichiometry of the reaction, it is clear that:
2 moles of KClO₃ = produces 3 moles of O₂
0.0135 moles of KClO₃ = produces (3/2)(0.0135)=0.02 moles of O₂
Mass of oxygen = (0.02mol)(32g/mol) = 0.64 g
Hence produced mass of oxygen is 0.64 grams.
To now more about mass & moles, visit the below link:
brainly.com/question/18983376
#SPJ1
Answer:
The hydrogen produces the smaller amount of ammonia.
Step-by-step explanation:
We are given the masses of two reactants, so this is a <em>limiting reactant problem</em>.
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 28.02 2.016 17.03
N₂ + 3H₂ ⟶ 2NH₃
Mass/g: 70.0 7.00
1. Calculate the moles of N₂ and H₂
Moles N₂ = 70.0 × 1/28.02
Moles N₂ = 2.498 mol N₂
Moles H₂ = 7.00 × 2.016
Moles H₂ = 3.472 mol N₂
=====
2. Calculate the moles of NH₃ from each reactant
<em>From</em> N₂:
The molar ratio is 2 mol NH₃/1 mol N₂
Moles of NH₃ = 2.498 × 2/1
Moles of NH₃ = 4.996 mol NH₃
<em>From</em> H₂:
The molar ratio is 2 mol NH₃/3 mol H₂
Moles of NH₃ = 3.472 × 2/3
Moles of NH₃ = 4.139 mol NH₃
======
3. Identify the limiting reactant
The limiting reactant is H₂, because it produces fewer moles of NH₃.
The answer is 0.841 g AgCl